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Fudgin [204]
3 years ago
5

Alonzo has completed 44 Deliveries so far this week he needs to make 55 deliveries for the week what percentage of his deliver

y has Alonzo completed?80%
Mathematics
1 answer:
bonufazy [111]3 years ago
6 0

Answer:

80%

Step-by-step explanation:

Find 44/55 and multiply the result by 100%:  (0.8)(100%) = 80% (completed)

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What are the coordinates of the point on the directed line segment from (- 3, - 9) to (4, 5) that partitions the segment into a
kompoz [17]

Answer:

(0,-1)

Step-by-step explanation:

Let the ends of the line segments be A(-4,3) and B(5,-6).

Ratio=4:5

By the concept of cordinate geometry,

x=(mx2+nx1)/(m+n)

y=(my2+ny1)/(m+n)

where m and n is the ratio m:n.

So, here the cordinates are

x={4(5)+5(-4)}/(4+5)

x=(20–20)/9

x=0

y={4(-6)+5(3)}/9

y={-24+15}/9

y=(-9)/9

y=(-1)

Therefore the cordinates of the point that divides the given line segment in the ratio 4 : 5 is (0,-1)

:)

5 0
3 years ago
Help me answer these please will give brainlst
Bumek [7]

Answer:

with what there is no question i see sorry

Step-by-step explanation:

7 0
3 years ago
Which set of ordered pairs does not represent a function?
weqwewe [10]

Answer:

{(0,0),(0,1),(1,2),(1,3)}

Step-by-step explanation:

If this was a function it would be (0,0) ,(1,1), (2,2) ,(3,3) and so on

4 0
3 years ago
Times for a surgical procedure are normally distributed. There are two methods. Method A has a mean of 33 minutes and a standard
lilavasa [31]

Answer:

Method A.

Step-by-step explanation:

For solving this question we need to find out the z-scores for both methods,

Since, the z-score formula is,

z=\frac{x-\mu}{\sigma}

Where, \mu is mean,

\sigma is standard deviation,

Given,

For method A,

\mu = 33

\sigma=8

Thus, the z score for 34 is,

z_1=\frac{34-33}{8}=0.125

While, for method B,

\mu = 37

\sigma = 4

Thus, the z score for 34 is,

z_2=\frac{34-37}{4}=-0.75,

Since, z_1 > z_2

Hence, method A is preferred if the procedure must be completed within 34 minutes.

8 0
4 years ago
A shock bolt follows a poison curve with an ability to perform 7 shocks every 10 min what are the odds of a random shock bolt be
Serhud [2]
0% chance because there can only be 7 shocks per 10 minutes. Or 7*3 shocks per 10*3 minutes (21 per 30), so it is impossible.
4 0
3 years ago
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