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3 years ago

Explin wht 4x3/5 = 12x 1/5

Mathematics

1 answer:

babymother [125]3 years ago

3 0

Answer:

0=0 True for all x

Step-by-step explanation:

4x3/5=12x1/5

Refine and expand

12/5x=12/5x

multiply both sides by 5

simplify

12x=12x

subtract 12 from both sides

0=0 True for all x

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Please answer asap! show work! 11. What is (f.g)(x)? f(x) = x3 +3 g(x) = 2x2 + x - 1

Ksenya-84 [330]

Answer:

2x⁵ + x⁴ - x³ + 6x² + 3x - 3

Step-by-step explanation:

Given :

f(x) = x³ + 3
g(x) = 2x² + x - 1

Finding (f × g)(x) :

f(x) × g(x)
(x³ + 3)(2x² + x - 1)
2x⁵ + 6x² + x⁴ + 3x - x³ - 3
2x⁵ + x⁴ - x³ + 6x² + 3x - 3

6 0

2 years ago

the flag pole in front of the school casts a shadow 40 feet long when the measurement of the angle of elevation to the sun is 31

san4es73 [151]

Answer:

I would say that the flag pole is about 120 feet long. Recall that this is an estimation.

Step-by-step explanation:

8 0

3 years ago

Syria has the 5 apps on her phone wich is 3 less than twice the amount the Khary has. How many apps does Khary have?

jek_recluse [69]

She has 7 apps on her phone

3 0

3 years ago

Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert

adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

$Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12}$ $= 60.67$

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: $s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}$

Put value in formula of Standard Deviation,

$s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}}$ = 40.75

Step-3: Then, we have to find the critical value by chi-square.

$X_{1-\alpha/2}^{2}=3.82$

$X_{1-\alpha/2}^{2}=21.92$

Then, find the confidence interval which is 95%.

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9$

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9$

5 0

3 years ago

Very appreciated if you can help^

Ivenika [448]

x-300

lolololololololol

8 0

3 years ago

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