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Zigmanuir [339]
3 years ago
6

You are sitting on the ground flying a kite.

Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer:

Height of the kite = 36 feet

Step-by-step explanation:

Triangle attached in the figure shows the complete picture,

I am sitting at point A, string connecting the kite and me is side AC, height of the kite from the ground is side BC and side AB representing the distance between me and the kite.

Length of side BC = h

Length of side AC = 39 feet

Length of side AB = 15 feet

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

(39)² = (15)² + h²

h² = 1521 - 225

h² = 1296

h = √1296

h = 36 feet

Therefore, kite is at 36 feet height.

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Answer:

a=4

Step-by-step explanation:

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How do u write 3 less than 9 times h
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Suppose that 20% of the residents in a certain state support an increase in the property tax. An opinion poll will randomly samp
aleksklad [387]

Answer:

95.44% probability the resulting sample proportion is within .04 of the true proportion.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sampling distribution of the sample proportion in sample of size n, the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.2, n = 400

So

\mu = 0.2, s = \sqrt{\frac{0.2*0.8}{400}} = 0.02

How likely is the resulting sample proportion to be within .04 of the true proportion (i.e., between .16 and .24)?

This is the pvalue of Z when X = 0.24 subtracted by the pvalue of Z when X = 0.16.

X = 0.24

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.24 - 0.2}{0.02}

Z = 2

Z = 2 has a pvalue of 0.9772.

X = 0.16

Z = \frac{X - \mu}{s}

Z = \frac{0.16 - 0.2}{0.02}

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Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

95.44% probability the resulting sample proportion is within .04 of the true proportion.

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3 years ago
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What is the value of the expression?
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Answer:

2.  92 ounces of Sprite

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Step-by-step explanation:

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4 ÷ 1/8

Copy dot flip

4 * 8/1

32 portions

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