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3 years ago

What is the mean of the prices below?

Mathematics

2 answers:

AleksAgata [21]3 years ago

7 0

The answer is 8 hope this helps :)

Elza [17]3 years ago

3 0

8 + 19 + 7 + 3 + 3 = 40

40/5 = 8

Your answer is D.

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Suppose you work for a company that manufactures electronics. The development analysts estimate that 5% of their flagship produc

givi [52]

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3 years ago

What is the y-intercept of the line

pychu [463]

My guess would be -54 because we are starting with -54

4 0

3 years ago

Larry was born on June 7, 1962. His little sister was born thirteen years and three days later. When was his sister born?

Viefleur [7K]

Answer:

The answer is B

Step-by-step explanation:

2021 - 1962 =59

59-13=46

2021-46=1975

Then 7+3=10

3 0

3 years ago

Please answer 26 and 27 please thank you

ser-zykov [4K]

Answer:

Part 26) $3\frac{1}{4}\ in$

Part 27) $2\frac{2}{3}\ cups$

Step-by-step explanation:

Part 26)

we know that

The length of Alana's hair was 9 3/4 inches

After her haircut, the length was 6 1/2 inches

To find out how many inches did she have cut subtract 6 1/2 from 9 3/4

but first

Convert mixed number to an improper fraction

$9\frac{3}{4}\ in=\frac{9*4+3}{4}=\frac{39}{4}\ in$

$6\frac{1}{2}\ in=\frac{6*2+1}{2}=\frac{13}{2}\ in$

Find the difference

$\frac{39}{4}-\frac{13}{2}=\frac{39-26}{4}=\frac{13}{4}\ in$

Convert to mixed number

$\frac{13}{4}\ in=\frac{12}{4}+\frac{1}{4}=3\frac{1}{4}\ in$

Part 27)

we have that

Emeril used a total of 7 1/4 cups of flour to make three pastries

He used 2 1/4 cup of flour for the first and 2 1/3 cups of flour for the second

To find out how much cups of flour Emeril use for the third pastry, subtract the sum of the cups of flour used in the first and second pastry from the total cups of pastry used

Let

x ----> number of cups of flour used in the third pastry

$x=7\frac{1}{4}-(2\frac{1}{4} +2\frac{1}{3})$

but first

Convert mixed number to an improper fraction

$7\frac{1}{4}\ in=\frac{7*4+1}{4}=\frac{29}{4}\ cups$

$2\frac{1}{4}\ in=\frac{2*4+1}{4}=\frac{9}{4}\ cups$

$2\frac{1}{3}\ in=\frac{2*3+1}{3}=\frac{7}{3}\ cups$

substitute

$x=\frac{29}{4}-(\frac{9}{4} +\frac{7}{3})$

$x=\frac{20}{4} -\frac{7}{3}$

$x=\frac{20*3-7*4}{12}$

$x=\frac{32}{12}\ cups$

Simplify

$x=\frac{8}{3}\ cups$

Convert to mixed number

$\frac{8}{3}=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}\ cups$

4 0

3 years ago

Need help checking my answers thanks!!

andre [41]

Answer:

yep thats right i think sorry hop i could help

6 0

3 years ago