Answer:
6/10
Step-by-step explanation:
all can be reduced to 2/5, except 6/10:
2/5
8/20=2/5 (divide out 4)
12/30=2/5 (divide out 6)
but not
6/10 = 3/5!
Complete question :
The denarius was a unit of currency in ancient Rome. Suppose it costs the Roman government 10 denarius per day to support 3 legionaries and 3archers. It only costs 3 denarius per day to support one legionary and one archer. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Answer:
No unique solution
Step-by-step explanation:
Given that:
Cost of supporting 3 legion aries and 3 archers = 10 denarius daily
Cost of supporting one legionary and one archer = 3 denarius
Let:
Legionaries = l ; archers = a
Equation for the first sentence :
3l + 3a = 10 - - - (1)
Second sentence :
l + a = 3 - - - - - (2)
From (2)
l = 3 - a
Substituting l = 3 - a into (1)
3(3 - a) + 3a = 10
9 - 3a + 3a = 10
9 - 0 = 10
The variable cancels out, Hence, ( there is no unique solution to find the cost of each soldier)
If your teacher allows the state test to be a percentage of your grade
The answer is negative three
Answer:
-4
Step-by-step explanation:
2 (-5 + 3)
2 (-5) + 2 (3)
-10 + 6
-4
Hope this was helpful :)