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3 years ago

11

if 10,500 is deposited in a compound interest account paying 2.99% interest annually how much will the account have after 5 year

s?

1 answer:

tamaranim1 [39]3 years ago

4 0

Amount = 10,500(1 + 0.0299) ^ 5

= 12,166.47

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Solve for x.<br><br><br><br> 9x - 1 = -11

leonid [27]

Answer:

X=-1.1 repeated

Step-by-step explanation:

9x - 1= -11

+1= +1

9x = -10

Divide by 9 on both sides

X = -1.1 repeating

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3 years ago

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2/3 of the product of 3/8 and 16

Radda [10]

You will have to cross multiply and also distribute the fractions like this:

2/3 of 3/8 times 16

so 3/8 times 16 is 6

Now take 2/3 of 6 and youll end up with 4! :)

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3 years ago

What is the value of x in the equation 4(2x 10) = 0? −5 −7 5 7

Alex73 [517]

4(2x+10)= 0
8x+40=0
subtract 40 from both sides
8x+40-40=0-40
8x=-40
x=-40/8
x=-5

4(2x-10)=0
8x-40=0
Add 40 from both sides
8x-40+40=0+40
8x=40
x=40/8
x=5

4 0

3 years ago

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Help please!What is the x-intercept of the line?X=33 Y=-22X=52 Y=-33X=71 Y=-44

tekilochka [14]

x intercept is -5

Explanation

Step 1

find the slope of the line:

when you know 2 points of the line, you can find the slope, by using:

$\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}$

then,Let

P1(33,-22)

P2(52,-33)

replace,

$\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-33-(-22)}{52-33}=\frac{-33+22}{19}=\frac{-11}{19} \\ \text{slope}=-\frac{11}{19} \end{gathered}$

Step 2

find the equation of the line

$y-y_1=slope(x-x_1)\rightarrow equation$

let

$\begin{gathered} \text{slope}=-\frac{11}{19} \\ P1(33,-22) \end{gathered}$

replace,

$\begin{gathered} y-y_1=slope(x-x_1)\rightarrow equation \\ y-(-22)=-\frac{11}{19}(x-33) \\ y+22=-\frac{11}{19}x+\frac{363}{19} \\ to\text{ isolate y, subtract 22 in both sides} \\ y+22-22=-\frac{11}{19}x+\frac{363}{19}-22 \\ y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \end{gathered}$

now, we have the equation of the line, to get the x intercetp ( it is when y=0)

replace

$\begin{gathered} y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \\ 0=-\frac{11}{19}x-\frac{55}{19} \\ \text{isolate x} \\ \frac{11}{19}x=-\frac{55}{19} \\ 11x=-\frac{55\cdot19}{19} \\ 11x=-55 \\ \text{divide both sides by 11} \\ \frac{11x}{11}=\frac{-55}{11} \\ x=-5 \end{gathered}$

so, the x intercetp is -5.

I hope this helps you

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1 year ago

What does 5(10a−2) equal

joja [24]

Answer:

50a-10

Step-by-step explanation:

because 5 x 10a = 50a then 5 x -2 = -10 because a negative x positive = negative

3 0

3 years ago

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