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3 years ago

What is the distance between (-6,4) and (-8,6)? Choose 1 answer:

Mathematics

1 answer:

lukranit [14]3 years ago

6 0

Answer:

Step-by-step explanation:

We want to find the distance between (-6, 4) and (-8, 6).

We can use the distance formula given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let (-6, 4) be (x₁, y₁) and let (-8, 6) be (x₂, y₂).

Substitute:

$d=\sqrt{(-8-(-6))^2+(6-4)^2$

Evaluate:

$d=\sqrt{(-2)^2+(2)^2$

Evaluate:

$d=\sqrt{4+4}=\sqrt{8}$

Hence, our answer is D.

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1∕2x – 2y + 2z –3z + 3∕4x – y

kogti [31]

Answer:

x-3y-z

Step-by-step explanation:

separate common terms and add them

1/2x+3/4x=1x

-2y-y=-3y

2z-3z=-1z

1x-3y-1z

6 0

3 years ago

Amalia is scuba diving at a position 24.25 feet below sea level. She descends 0.5 foot each minute for 25 minutes. What is Amali

Inga [223]

Answer:

36.75 feet below sea level

Step-by-step explanation:

Feet she descended in 25min

=0.5×25

=12.25

Therefore, the total feet she dived to

=12.25+24.25

=36.75

5 0

3 years ago

Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m

Dovator [93]

Option a: $\frac{m^{5} }{162n}$ is the equivalent expression.

Explanation:

The expression is $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ where $m\neq 0, n\neq 0$

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

$\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }$

Cancelling the like terms, we have,

$\frac{3^{-3}m^{5} n^{-1}}{6 }$

This equation can also be written as,

$\frac{m^{5}}{3^{3}6 n^{1} }$

Multiplying the terms in denominator, we have,

$\frac{m^{5} }{162n}$

Thus, the expression which is equivalent to $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ is $\frac{m^{5} }{162n}$

Hence, Option a is the correct answer.

8 0

3 years ago

Read 2 more answers

What is the range for a x intercept of (5,0) and a y intercept of (0,3)

Nastasia [14]

Answer:

(5,0)=x1,y1

(0,3)=x2,y2

so the range will be x1-x2/

3 0

3 years ago

Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated

Dafna11 [192]

<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0

3 years ago