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3 years ago

What is the distance between (-6,4) and (-8,6)? Choose 1 answer:

Mathematics

1 answer:

lukranit [14]3 years ago

6 0

Answer:

Step-by-step explanation:

We want to find the distance between (-6, 4) and (-8, 6).

We can use the distance formula given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let (-6, 4) be (x₁, y₁) and let (-8, 6) be (x₂, y₂).

Substitute:

$d=\sqrt{(-8-(-6))^2+(6-4)^2$

Evaluate:

$d=\sqrt{(-2)^2+(2)^2$

Evaluate:

$d=\sqrt{4+4}=\sqrt{8}$

Hence, our answer is D.

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3 years ago

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3 years ago

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Cedarburg's zoo has two elephants. The male elephant weighs 3 3/4 tons and the female

gtnhenbr [62]

Answer:

3.16666667 tons

Step-by-step explanation:

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2 years ago

Maggie’s brother is 12 years younger that three times her age . The sun of their ages is 44 . How old is Maggie

meriva

I'm not sure if this is right but you can set up an equation and solve to find Maggie's age:

Maggie's brother's age = b
Maggie's age = m

b = 12 - 3m
44 = 12-3m
12-3m = 44
-12 -12
-3m = 32
÷ 3 ÷3
m = 10.67

So this would be Maggie's age

I hope this helped :)

7 0

3 years ago

For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?

DaniilM [7]

<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

$x\neq 1$

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

$\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]$

Now, the determinant of this matrix is:

$\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1$

Hence,

$-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1$

4 0

3 years ago