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marin [14]
3 years ago
8

-5 5/6 + (-8 4/5)= what show the work

Mathematics
1 answer:
djverab [1.8K]3 years ago
6 0

Answer:

-13 2/3

Step-by-step explanation:

-5 5/6               5x6= 30 4x5= 20

+                                20/30= 2/3

-8 4/5

-----------      -5 + -8 = -13

-13  2/3

hope this helps

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The graph of which function will have a maximum and a y-intercept of 4? f(x) = 4x2 + 6x – 1 f(x) = –4x2 + 8x + 5 f(x) = –x2 + 2x
V125BC [204]

Answer:

Option C (f(x) = -x^2 + 2x + 4)

Step-by-step explanation:

In this question, the first step is to write the general form of the quadratic equation, which is f(x) = ax^2 + bx + c, where a, b, and c are the arbitrary constants. There are certain characteristics of the values of a, b, and c which determine the nature of the function. If a is a positive coefficient (i.e. if a>0), then the quadratic function is a minimizing function. On the other hand, a is negative (i.e. if a<0), then the quadratic function is a maximizing function. Since the latter condition is required, therefore, the first option (f(x) = 4x^2 + 6x - 1) and the last option (f(x) = x^2 + 4x - 4) are incorrect. The features of the values of b are irrelevant in this question, so that will not be discussed here. The value of c is actually the y-intercept of the quadratic equation. Since the y-intercept is 4, the correct choice for this question will be Option C (f(x) = -x^2 + 2x + 4). In short, Option C fulfills both the criteria of the function which has a maximum and a y-intercept of 4!!!

7 0
3 years ago
Read 2 more answers
Any help towards finding out Part B and C would be greatly appreciated!
Alika [10]
Part B: I think the relation that has the greater value when x=6 is f(x) = 7x - 15 because:

7(6) - 15 = 27 which is greater than the output of 14.

Part C: the value of x would be 3 because:

f(x) = 7x - 15
6 = 7x - 15
+ 15 +15
21 = 7x
3 = x

Sorry if any of this is wrong.
6 0
3 years ago
1/2(12w+8)-1/8(10w-5) This confuses me very much pls help
Nostrana [21]

Answer:

follow xxflirtykingxx

6 0
2 years ago
Read 2 more answers
Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.
solong [7]

Answer:

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 24.4, \sigma = 1.2

In this problem, a value x is significantly high if:

P(X \geq x) = 0.01

Using these​ criteria, is a​ back-to-knee length of 26.6 in. significantly​ high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.6 - 24.4}{1.2}

Z = 1.83

Z = 1.83 has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0
3 years ago
How do you find the domain on a graph
nadya68 [22]

The domain is all the input values that's shown on the x-axis on the graph.

7 0
3 years ago
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