They will pay $559.65,rounded will be $560.00.
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Answer:
Area of Triangle QRP = 3
Step-by-step explanation:
According to Question , We have a circle With Centre 'O' & Area 48
.
Area Of Circle = 48

= 48
r = 
Now We Have Two Points Given On Circle Q & R , P Is Circumcentre Of Triangle QRO .
Thus A Circle Can Also Be Formed with Centre P . ( See attachment For Diagram )
Now The Diameter of Circle With Centre P = Radius Of Circle with Centre O
so Radius Of Circle With Centre P(
) = 
Now We Have To Find Area Of Equilateral Triangle .
A =
A= 
The Area Of PQR is = 3
For Diagram , Please Find In Attachment
Answer:
first triangle (to left) b=8, second one c=17
Step-by-step explanation:
for the first triangle (one to the left) the hypotenuse is 9, so let's use the pythagorean formula.
A^2 + B^2 = C^2
^ ^ ^
^ ^ Hypotenuse
^ second side
first side
Substitute:
5^2 + b^2 = 9^2
SImplify:
25+b^2 = 81
Reduce:
b^2 = 64
Simplify:
b=8
In the second triangle, we are given 2 sides.
Let's do the same thing we did in the first one.
Givens:
A = 8
B = 15
Find:
C
Substitute:
8^2 + 15^2 = c^2
Simplify
64 + 225 = c^2
Reduce:
289 = c^2
Let's now square root both sides
square root of 289 is 17
so we are left with this:
c=17
Phew, you did it!
Hope this helped :))