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3 years ago

Can anyone help me with this math problem

Mathematics

1 answer:

Gnoma [55]3 years ago

5 0

Answer:

B.)

Step-by-step explanation:

In step #1 they did the distributive property

2/5 × 15x = 6x

2/5 × -30y = -12y

The new equation would be:

6x - 12y + 10x

Further Explanation

They then combined 6x + 10x to get 16x

16x - 12y

They then factored it out to 4(4x - 3y)

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3 years ago

A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju

weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

$V_0 = 12 m/s$

$\theta = 20^0$

$g=9.8 m/s^2$

At maximum height:

$V_y = 0$

Components of initial velocity:

$V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s$

$V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s$

To find time to reach maximum height:

$V_y = V_0y -gt$

Plugging in the known values:

0 = 4.10 - 9.8t

$t = \frac{-4.10}{-9.8}$

$t = 0.418 s$

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

$x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m$

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3 years ago