4x+7y=19<br> Y=x+9<br><br> U must solve it in substitution method

In rectangle ABCD the diagonals intersect each other at point O and m∠ABD = 30°. Find BC if AC = 16 in

pashok25 [27]

16(sin 30degrees) = BC

BC = 8

4 0

2 years ago

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7x+2y=3 and x-3y=30, what is the value of y?

Blizzard [7]

$\tt\it\bf\it\huge\bm{\mathfrak{{\red{hello*mate♡}}}}$

$\tt\it\bf\huge\it\bm{\mathcal{\fcolorbox{blue}{yellow}{\red{ANSWER==>}}}}$

_______________________________

<h3>I'm solving it using substitution method:-</h3>

<h3>7x+2y=3 {given}</h3>

<h3>x-3y=30 {given}</h3>

<h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3>

<h3>putting the value of y on eqn(1):-</h3>

<h2>Hence, x=3, y= -9</h2>

✌️✌️❤️❤️

_______________________________

$\tt\it\bf\huge\it\bm{\mathcal{\fcolorbox{blue}{yellow}{\red{BE-BRAINLY !}}}}$

5 0

2 years ago

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6 in.

asambeis [7]

Answer:

152 square inches

Step-by-step Explanation:

To answer this, please look at the picture below. We can find the area by separating and combine the value of areas after calculating three values for each areas. (Notice that when we separate them, we get three rectangles which we can use the formula of width × length)

We should get 80+48+24 which add up to 152.

In case if you are confused which parts you don't understand in these photos, you can ask in the comment.

5 0

2 years ago

23.450÷345<br><img src="https://tex.z-dn.net/?f=23.450%20%5Cdiv%20345" id="TexFormula1" title="23.450 \div 345" alt="23.450 \div

wariber [46]

Answer:

0.0679710145

I hope this will help you

3 0

2 years ago

In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem

Damm [24]

Answer:

a) P(A) = 0,4607 or P(A) = 46,07 %

b) P(B) = 0,7120 or 71,2 %

c) P(C) = 0,2055 or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )! ⇒ C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2 ⇒ C ( 24,4) = 10626

TE = 10626

Splitting the group of tanks in two 6 with h-v and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3) = 6 * 18! / 3!*15! = 18*17*16*15!/15!

FE = 4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607 or P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2 = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120 or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2 ⇒ FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055 or P(C) = 20,55 %

5 0

2 years ago

4x+7y=19 Y=x+9 U must solve it in substitution method