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Artemon [7]
3 years ago
13

Write the standard form of the equation of the line through the given point with the given slope.

Mathematics
1 answer:
lisov135 [29]3 years ago
6 0

Answer:

The equation for this slope will be y=7x-5

Step-by-step explanation:

Hope this helped

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as the age of cars increases , its value decreases which correlation best represents this relationship ?
marta [7]

hi <3

this type of correlation is called a negative correlation

hope this helps :)

7 0
3 years ago
A jar contains a combination of 60 nickels and dimes worth a total of $4.30. suppose that is deemed desirable to determine how m
Taya2010 [7]
We will represent everything in cents
nickles are worth 5 cents and dimes are 10 cents
n=number of nickles
d=number of dimes



60 total coins
n+d=60


total is 430 cents

5n+10d=430
divide both sides by 5
n+2d=86

we gots

n+d=60 and
n+2d=86
eliminate

multiply first equation by -1 and add to 2nd equation

-n-d=-60
<u>n+2d=86 +</u>
0n+1d=26

d=26

so

n+d=60
n+26=60
n=34


34 nickles and 26 dimes
6 0
3 years ago
What expression is equivalent to (3^2)^-2
MariettaO [177]

Answer:

1/81

Step-by-step explanation:

You just tap the calculator

6 0
3 years ago
Read 2 more answers
A 3-pack of jump ropes costs $6.90. What is the unit price?
polet [3.4K]

Answer:

$2.30 for each jump rope.

Step-by-step explanation:

6.90 / 3 = 2.3

4 0
3 years ago
Read 2 more answers
An electronics company just finished designing a new tablet computer and is interested in estimating its battery-life. A random
Alika [10]

Answer:

6 \pm 2.861(0.3354)

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.861.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.861\frac{1.5}{\sqrt{20}} = 2.861(0.3354)

In which s is the standard deviation of the sample and n is the size of the sample.

The format of the confidence interval is:

S_{M} \pm M

In which S_{M} is the sample mean

So

6 \pm 2.861(0.3354)

7 0
3 years ago
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