NEED HELP ASAP AGAIN

Mathematics

2 answers:

balu736 [363]4 years ago

8 0

4)
A=1/2 bh
A = 1/2(6)(3)
A = 9 in^2

5)
A=1/2 bh
A=1/2(7)(10)
A = 35 m^2

6)
A=1/2 bh
A=1/2(5)(8)
A=20 ft^2

7)
A=1/2 (b1+b2)h
A=1/2 (5+10)8
A=60 in^2

8)
A=1/2 (b1+b2)h
A=1/2 (13+19) 10
A=160 mm^2

9)
A=1/2 (b1+b2)h
A=1/2 (3+6) 2
A = 9 ft^2

Reptile [31]4 years ago

7 0

4)A=1/2 bh
A = 1/2(6)(3)
A = 9 in^2

5)A=1/2 bh
A=1/2(7)(10)
A = 35 m^2

6)A=1/2 bh
A=1/2(5)(8)
A=20 ft^2

7)A=1/2 (b1+b2)h
A=1/2 (5+10)8
A=60 in^2

8)A=1/2 (b1+b2)h
A=1/2 (13+19) 10
A=160 mm^2

9)A=1/2 (b1+b2)h
A=1/2 (3+6) 2
A = 9 ft^2

You might be interested in

You make punch for a party. The ratio og ginger ale to fruit juice is 8 cups to 3 cups. You decide to add 4 more cups of ginger

Dvinal [7]

To get the answer we can use proportion
8 ginger ----------------- 3 fruit
12 ginger ----------------x
Crossmultiply now
8x=12*3 /:8
x= $\frac{12*3}{8}$
x=<u /> $\frac{36}{8} \\ x=4.5$
To not change ratio we have to have 4.5 cups of fruilt juice. We initialy had 3, so we have to add 1.5 cup of fruit juice.

7 0

4 years ago

The function h(t) = −16t2 + 110t + 72 models the height h, in feet, of an object above ground t seconds after being launched str

marissa [1.9K]

<h2>Answer:</h2>

We have the following function:

$h(t)=-16t^2+110t+72$

And this function models the height $h$ , in feet, of an object above ground $t$ seconds after being launched straight up in the air. The graph of this function is shown below. So we want to know what the number 72 represents. Well, what if $t=0$ ?

If $t=0$ we have:

$h(0)=-16(0)^2+110(0)+72 \\ \\ \boxed{h(0)=72}$

Thus, <em>72 is the height of the object above the ground at $t=0$ . In other words, 72 is the initial height of the ball before being launched straight up in the air.</em>