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agasfer [191]
3 years ago
12

The length of a rectangle is represented by (6x-2), and the width is represented by (x-1). Which expression best represents the

perimeter of the rectangle?
A) 14x - 6
B) -8x +2
C) 6x^2 - 8x
D) 6x^2 - 8x +2
Thanks!

Mathematics
2 answers:
NARA [144]3 years ago
3 0
The answer should be A

Ipatiy [6.2K]3 years ago
3 0
The length of a rectangle is represented by (6x-2), and the width is represented by (x-1). Which expression best represents the perimeter of the rectangle?
A) 14x - 6

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Using the diagram, if angle 3 + angle 4 is a straight line then what is the total<br> measure?
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5 0
2 years ago
What’s the value of y ?
andreev551 [17]
X = 3. So 3x3 is 9, and then subtract 2 is 7. Y=7 Answer is B.
5 0
3 years ago
Subtract 7x^2−5xy+8y^2 from −2x^2−15xy+9y^2
Ghella [55]

Answer:

y^2-10xy-9x^2

Step-by-step explanation:

We want to subtract 7x^2 -5xy+8y^2 from -2x^2-15xy+9y^2.


We set up the subtraction problem as follows:


(-2x^2-15xy+9y^2)-(7x^2-5xy+8y^2).


We expand the brackets to obtain;


=-2x^2-15xy+9y^2-7x^2+5xy-8y^2.


We regroup the terms to obtain;


=9y^2-8y^2-15xy+5xy-2x^2-7x^2.


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4 0
3 years ago
Please help quick!!<br>​
Nataly [62]

Hi !

∫ \frac{t}{t + 1}dt

We need to prove that it is equal to

∫ \frac{u - 1}{u}du

As per given options, Substitute <em>u</em> by <em>t</em><em>+</em><em>1</em><em> </em>

=  > ∫ \frac{u - 1}{t + 1} du

<em>Then</em><em> </em><em>given</em><em> </em><em>t</em><em> </em><em>=</em><em> </em><em>u</em><em>-</em><em>1</em>

=  > ∫ \frac{t}{t + 1} du

Then substitue the third given value also

=  > ∫ \frac{t}{t + 1} dt

Therefore, it's <u>proved</u>

~<em>Hop</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em>s</em>

7 0
3 years ago
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