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mestny [16]
3 years ago
5

suppose that x and y vary inversely and x=1 when y=12. write a function that models the inverse variation. graph the function an

d find y when x=5
Mathematics
1 answer:
larisa [96]3 years ago
6 0

Answer:

y=12/x

Step-by-step explanation:

if y=12, and x=1 so

general formula y=12/x

for x=5 , y=12/5=2.4

you can graph by ploting points such as (1,12), (5, 2.4),...

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3 years ago
Hi can someone help me with this pleaseee
AveGali [126]

Second choice.

Which is 1591.1 cm^2.

3 0
2 years ago
which expression represents purely real numbers and which expression represents non-real complex number?​
Lyrx [107]

Answer:

Step-by-step explanation:

Complex numbers are the numbers represented by the expression = a + bi

Here a = real part of the number

bi = imaginary part

a and b are the real numbers.

i^9=(i^2)^4.(i)

    =(-1)^{4}.i [Since, i^2=-1]

    =i

Therefore, its a non real complex number.

2 - \sqrt{-49} = 2-\sqrt{(-1)(7)^2}

               = 2-7\sqrt{-1}

               = 2-7i

This number is a Non real complex number.

\sqrt{(-18)^2}=18\sqrt{-1}

              = 18i

It's a non real complex number.

3 + 2i

It's a non real complex number.

-289

It's a purely real number.

4-32i^2=4-32(-1)

             = 4 + 32

             = 36

It's a purely real number.

6 0
3 years ago
Use the slope formula to find the slope of the
muminat

Answer:

m= 2/17

Step-by-step explanation:

do the formula x1 and y1 and x2 and y2

x1, y1   x2, y2

(-11,15) (23,19)

when subtracting you ALWAYS START WITH YOUR Ys

19-15= 4

now subtract your Xs

23- (-11)= 34

now your answer is 4/34

but that's not the last step you can simplify it and make it smaller,

they both go into 2 so know divide both of then numbers by 2

and you should get 2/17

your final answer should be 2/17

4 0
2 years ago
Read 2 more answers
Solve by using square root: <br> 4(x-1)^2+2=10
Scilla [17]
4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}

Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}


3 0
3 years ago
Read 2 more answers
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