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Serhud [2]
3 years ago
11

A city government adds streetlights within its boundaries at a total cost of $300,000. These lights should burn for at least 10

years but can last significantly longer if maintained properly. The city develops a system to monitor these lights with the goal that 97 percent will be working at any one time. During the year, the city spends $48,000 to clean and repair the lights so that they are working according to the specified conditions. The city also spends another $78,000 to construct lights for several new streets. Prepare the entries assuming infrastructure assets are capitalized with depreciation recorded on government-wide financial statements. Prepare the entries assuming infrastructure assets are capitalized with government using the modified approach on government-wide financial statements.
Business
1 answer:
tekilochka [14]3 years ago
3 0

Answer: See explanation

Explanation:

a. Prepare the entries assuming infrastructure assets are capitalized with depreciation recorded on government-wide financial statements.

1. Debit: Infrastructure assets—street lights $300,000

Credit: Cash $300,000

(To record cash purchase of street light

2. Debit: Depreciation expense $300,000/10 = $30,000

Credit: Accumulated depreciation—infrastructure assets $30,000

(To record depreciation expense)

3. Debit: Maintenance expense—infrastructure assets $48000

Credit: Cash $48000

(To record maintenance expense)

4. Debit: Infrastructure assets—street lights $78000

Credit: Cash $78000

(To record cash expense for new light)

b. Prepare the entries assuming infrastructure assets are capitalized with government using the modified approach on government-wide financial statements.

1. Debit: Infrastructure assets—street lights $300,000

Credit: Cash $300,000

(To record purchase of street light)

2. Debit: Maintenance expense—infrastructure assets $48000

Credit: Cash $48000

(To record maintenance expense)

3. Debit: Infrastructure assets—street lights $78000

Credit: Cash $78000

(To record cash expense for new light)

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1. La fórmula P=2L + 2W es para encontrar el perimetro P de un rectángulo con longitud L y
Rus_ich [418]

Answer:

P=7.2m

Explanation:

In a figure or surface, the perimeter refers to the contour and the measure of that contour. In other words, the perimeter is the sum of all the sides of the figure. In this way, the perimeter allows calculating the boundary of a surface, making it very useful.

The problem provided you the formula to find the perimeter P of a rectangle of length L and width W:

P=2L+2W

So, in order to find the perimeter of a rectangular garden of

Length=L=1.2m

and

Width=W=2.4m

You just need to replace these data into the provided formula:

P=2(1.2)+2(2.4)=2.4+4.8=7.2m

<em><u>Translation:</u></em>

En una figura o superficie, el perímetro se refiere al contorno y a la medida de ese contorno. En otras palabras, el perímetro es la suma de todos los lados de la figura. De esta manera, el perímetro permite calcular la frontera de una superficie, por lo que resulta de gran utilidad.

El problema le proporcionó la fórmula para encontrar el perímetro de un rectángulo de largo L y ancho W:

P=2L+2W

Entonces, para encontrar el perímetro de un jardín rectangular de

Longitud=L=1.2m

Y

Ancho=W=2.4m

Solo necesita reemplazar estos datos en la fórmula provista:

P=2(1.2)+2(2.4)=2.4+4.8=7.2m

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If you were using a simple exponential smoothing forecast model (alpha value equal to 0.30) that generated a forecast of 25.10 u
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Why is it important to research other jobs that require the same education and training?
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YellowCard Company manufactures accessories for iPods. It had the following selected transactions during 2017. (Note: For any pa
jarptica [38.1K]

Answer:

warrant expense 51,000 debit

          cash                       6,000 credit

          warranty liability 45,000 credit

--to record warrant-related accounts--

interest payable 16,667 debit

interest expense  3,333 debit

          cash                  20,000 credit

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That is: 200,000 x 10% x 10/12 months = 16,667 payable

At February 28th we recognize the last two month of interest

200,000 x 10% x 2/12 months = 3,333 expense

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Facility: the asset should add to all the cost necessary to acquire it:

As the conversion into community center is mandatory it is part of the cost:

present value of the 500,000 in ten years:

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $500,000.00

time  10.00

rate  0.10000

\frac{500000}{(1 + 0.1)^{10} } = PV  

PV   192,771.6447

Total cost:

5,000,000 cashg + 192,772 liability = 5,192,772

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