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Equation
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y = -3x - 9
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Option 1
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If I substitute x = -9, I should get y = 0
When x = -9
y = -3 (-9) - 9
= 18 (I did not get 0, wrong)
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Option 2
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If I substitute x = -3, I should get y = 0
y = -3(-3) - 9
y = 9 - 9
y = 0 (Yes, I got 0, correct)
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Option 3
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If I substitute x = 0, I should get y = -3
y = -3 (0) - 9
y = 0 - 9
y = -9 (I did not get -3, wrong)
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Option 4
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If I substitute x = 0, I should get y = -9
y = -3 (0) - 9
y = 0 - 9
y = -9 (Yes, I got -9, correct)
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Answer: (-3, 0) and (0, 9) are ordered pairs of the equation (Answer B, D)
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The distance is (-4, 4)
Explanation: I moved down 4 cubes (negative) and moved right 4 cubes (positive).
I hope I am right :)
Answer:
The length of the line segment UV is 76 units
Step-by-step explanation:
In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length
In Δ ONT
∵ U is the mid-point of ON
∵ V is the mid-point of TN
→ That means UV is joining the mid-points of two sides
∴ UV // OT
∴ UV = 
OT
∵ UV = 7x - 8
∵ OT = 12x + 8
∴ 7x - 8 = (12x + 8)
→ Multiply the bracket by
∵ (12x + 8) = (12x) + (8) = 6x + 4
∴ 7x - 8 = 6x + 4
→ Add 8 to both sides
∴ 7x - 8 + 8 = 6x + 4 + 8
∴ 7x = 6x + 12
→ Subtract 6x from both sides
∴ 7x - 6x = 6x - 6x + 12
∴ x = 12
→ Substitute the value of x in the expression of UV to find it
∵ UV = 7(12) - 8 = 84 - 8
∴ UV = 76
∴ The length of the line segment UV is 76 units
Let's examine the given function first:
f(x) = x^2 + 1 is the same as f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept: f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)
Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.
