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Korvikt [17]
3 years ago
6

What is the solution for this inequality? need help fast please!​

Mathematics
2 answers:
nevsk [136]3 years ago
8 0

Answer:

x\geq -4

Step-by-step explanation:

-10x\leq 40

divide by -10, which means you need to flip the inequality sign since youre dividing by a negative number

x\geq -4

Nady [450]3 years ago
7 0

Answer:

The anwer is D

Step-by-step explanation:

up up up......

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A certain drug dosage calls for 17 mg per kg per day and is divided into two doses (1 every 12 hours). If a person weighs 255 po
vekshin1

Answer:

985.15mg

Step-by-step explanation:

Calculation for how many milligrams of the drug should he receive every 12 hours

First step is to calculate the weight in kg

255 lbs = 255/2.2 = 115.9 kg

Second step is multiply mg/kg in order to get total medicine per day

Dose per day=115.9kg × 17 mg

Dose per day= 1,970.3

Third step is to calculate how many milligrams of the drug should he receive by dividing the day dose by 2

Dose milligrams=1,970.3/2

Dose milligrams=985.15mg

Therefore how many milligrams of the drug should he receive every 12 hours will be 985.15mg

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3 years ago
Suppose the graph of a cubic polynomial function
galina1969 [7]

Answer:

Y= - 5

X=0

Y=1-x. Intercept. Put x=0

X=1-y.intercept.put y=0

Slope = y-y1/x-x1 =0+5/0-0 = not answer Undecided value

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3 years ago
¿cual es la solucion de la siguiente ecuacion (10+2x +x= -x +18)?
n200080 [17]

Answer:

x=2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df
rjkz [21]

Answer:

a) For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

b) For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

Part b

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

3 0
3 years ago
Angle KLM and angle MLN are a linear pair.
VashaNatasha [74]

Answer: Angles RLN and MLK would be vertical angles.

Step-by-step explanation:

5 0
2 years ago
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