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shtirl [24]
2 years ago
8

Can someone help, please

Mathematics
1 answer:
mars1129 [50]2 years ago
3 0

Answer:

I think it is C. Number cube

Let 1,2 = pop

Let 3,4 = jazz

Let 5, 6 = rock

Roll cube two times. Repeat.

Step-by-step explanation:

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Evaluate the given expression if x = 25, y = 10, w = 11, and z = 18.<br><br> (see the image)
hammer [34]

Answer:

D

Step-by-step explanation:

So we have the expression:

(x-y)^2+10wz

And we want to evaluate it when x=25, y=10, w=11, and z=18.

So, substitute these values for the variables:

=(25-10)^2+10(11)(18)

First, subtract within the parentheses:

=(15)^2+10(11)(18)

Square 15:

=225+10(11)(18)

Now, multiply the terms on the right. 10 times 11 is 110:

=225+110(18)

Multiply:

=225+1980

Finally, add:

=2205

So, our answer is D.

And we're done!

8 0
3 years ago
Read 2 more answers
if you were to solve the following system by substitution what would be the best variable to solve and from what equation? 2x+8y
Nina [5.8K]
All the numbers in the first equation have a common factor of 2. Removing that gives
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y

My choice would be to solve for x using the first equation.

_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35

4 0
3 years ago
If i clock out at 11:53 and i have 30 Minutes what time do i get in?
lara [203]

Answer:

you get in at 11:23

Step-by-step explanation:

53-30=30

so 11:23

6 0
2 years ago
Read 2 more answers
Solve 10e^2x - 5 =23^x for x.
yawa3891 [41]

10e^{2x}-5=23e^x\qquad\text{subtract}\ 23e^x\ \text{from both sides}\\\\10e^{2x}-23e^x-5=0\\\\10(e^x)^2-23(e^x)-5=0\\\\\text{substitution:}\ e^x=t > 0\\\\10t^2-23t-5=0\\\\10t^2-25t+2t-5=0\\\\5t(2t-5)+1(2t-5)=0\\\\(2t-5)(5t+1)=0\iff2t-5=0\ \vee\ 5t+1=0\\\\2t=5\ \vee\ 5t=-1\\\\t=\dfrac{5}{2} > 0\ \vee\ t=-\dfrac{1}{5} < 0\\\\\text{therefore}\ e^x=\dfrac{5}{2}\to\ln e^x=\ln\left(\dfrac{5}{2}\right)\\\\\boxed{x=\ln\left(\dfrac{5}{2}\right)}

5 0
2 years ago
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0.88 kilogram what is the value of the digit in the tents place
Orlov [11]
The value of the tenths place is 8
7 0
3 years ago
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