What is the greatest common factor of 16 and 40?

Kendra was asked to find the number of students who planned to attend the evening symphony performance. She was told that 40 per

navik [9.2K]

Picture related to the question is attached below

Answer:

Kendra should have divided by 2 instead of multiplying by 2

Step-by-step explanation:

40 percent = percentage who plan to attend

100% = total percentage of student

From the question ;

When reducing percentages, division is employed and this the equation should be :

40/2 ÷ 100/2

40/2 * 2/100

20 * 1/50

20/50

= 0.4

0.4 * 50

= 20 students

6 0

2 years ago

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A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago

Construct a polynomial function with the following properties: fifth degree, 5 is a zero of multiplicity 4, −4 is the only other

mario62 [17]

5(x-5)^4(x+4)
you raise x-5 to the 4th power because 5 has a multiplicity of 4

5 0

3 years ago

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01:57:09 In a city, the distance between the library and the police station is 3 miles less than twice the distance between the

tester [92]

Answer:

Distance between the police station and the fire station be 4 miles

Step-by-step explanation:

Let distance between the police station and the fire station be x miles.

The distance between the library and the police station is 3 miles less than twice the distance between the police station and the fire station.

Distance between the library and the police station $=2x-3$

Also, distance between the library and the police station is 5 miles.

$2x-3=5\\2x=3+5\\2x=8\\x=\frac{8}{2}\\ x=4\,\,miles$

8 0

3 years ago

Will award Brainlyest!!! Choose the equation that represents a line that passes through points (−3, 2) and (2, 1).

Pachacha [2.7K]

Answer:2. Rate of change, or slope, is the change in y over change in x. Remember that a point is given in (x, y). Also that you need two points to find the change.

If you have two points, (x1, y1) and (x2, y2), the rate of change or slope

In your problem, the given points are (0, -1) and (2, -11)

The "initial value" is the y-intercept - where the graph intersects the y-axis and also where x = 0. The given point (0, -1) has x = 0, so the initial value is -1.

4. Remember the model equation for a graph of a line is

y = mx + b,

where m is slope and b is y-intercept - where the graph intersects the y-axis and also where x = 0.

The x-axis of the graph would be number of weeks, since it is independent.

The y-axis of the graph would be how much money she has.

Since she starts (at 0 weeks) at $25, the first point would be (0, 25). Notice here that it is the y-intercept since x = 0. The value of b in the model equation of a line y = mx + b would be 25.

The rate of change, or slope, is $5/week. This is m in the model equation of a line y = mx + b.

Putting b = 25 and m = 5 into the model equation y = mx + b (remember we use this equation because it works for all lines), the equation would be

y = 5x + 25.

4.

The slope of this will be -0.5degrees/hr, or just -0.5 if it is used as m in the

y = mx+b equation. The slope is negative because it "decreases".

5.

Plot each point and connect the dots. Remember the first number corresponds to the x-axis and the second to the y-axis.

For example in the table for x = -2 and y = -6, the point is (-2, -6), and from the origin (0,0) you go left 2 on the x-axis and down 6 to plot the point.

9.

I think you can do this if you can do #3, but now you have to find b by plugging in given values.

y = mx + b

y = 1212x + b

We can plug in the given point (3,1) to find b.

1 = 1212(3) + b

b = -3625

y = 1212 - 3625

10. Don't know which function you are referring to.

The slope is $10/week, or m = 10.

A point is (4, 90) because "After 4 weeks, Roberta has $90."

The y-intercept is 50 because x (weeks) = 0 at that time.

y = mx + b

y = 10x + 50

8 0

2 years ago

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