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Shkiper50 [21]
2 years ago
11

What is the domain of this function? 

Mathematics
1 answer:
hichkok12 [17]2 years ago
5 0

Answer:

no real numbers

Step-by-step explanation:

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3x + 3y =15 and x = -3y -1
saul85 [17]

Answer:

  (x, y) = (8, -3)

Step-by-step explanation:

You can substitute for x in the first equation:

  3(-3y -1) +3y = 15

  -6y = 18 . . . . . add 3 and simplify

  y = -3 . . . . . . . divide by -6

  x = -3(-3) -1 = 8 . . . . find x using the second equation

The solution to this system of equations is (x, y) = (8, -3).

4 0
2 years ago
Which of the following relations describes a function?
grin007 [14]
It’s c because none of the c values repeat
6 0
3 years ago
Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0<×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
I will give brainiest if random will report please include the expression in answer
Mandarinka [93]

(m - 1/2) + 25

Plz give me brainlest

7 0
2 years ago
Read 2 more answers
Supongamos que estás en el infierno y el diablo te reta a un juego. Él piensa en un número natural.Cada día, tú tendrás una opor
Blababa [14]

Answer:

En síntesis, se inicia con el número natural más pequeño en el primer y se prosigue con los números siguientes en caso de no dar con n, de modo que el participante pasará en el infierno únicamente n días, algo pequeño en comparación con la eternidad.

Step-by-step explanation:

Los números naturales comprenden el subconjunto más pequeño de los números reales conformado por los siguientes elementos:

\mathbb{N} = \{1,2,3,4,...\}

Sea n \in \mathbb{N} el número que tiene el diablo en su mente, tal que n \geq 1. Comenzamos el primer día con 1, si este no corresponde con n. Entonces se utiliza 2 al día siguiente y este no corresponde, se emplea al día siguiente y así sucesivamente hasta conseguir n.

En síntesis, se inicia con el número natural más pequeño en el primer y se prosigue con los números siguientes en caso de no dar con n, de modo que el participante pasará en el infierno únicamente n días, algo pequeño en comparación con la eternidad.

6 0
3 years ago
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