Answer:
291/100
Step-by-step explanation:
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
Answer:
Step-by-step explanation:
commission from sale of $32,000 = $32,000 x 4% = $1,280
Suppose sales would double, comission would be doubled too.
Assume sales be S and commission be C
C = S * 4% (they have a linear positive relation)
if S double to 2S, new commission = (2S)*4% = 2*(S*4%) = 2 (old commission)
Sent a picture of the solution to the problem (s).
The correct answer is B. Hypothesis
