All categories

3 years ago

Help please 34 points

Mathematics

2 answers:

e-lub [12.9K]3 years ago

5 0

Answer:

B is the correct answer

Step-by-step explanation:

fredd [130]3 years ago

4 0

Answer:

B is ans ..................

You might be interested in

The two triangles are similar, what is the measure of angle L?

gtnhenbr [62]

ABC is similar to JKL. Notice how C is the right angle (90 degrees) as shown by the square angle marker. Angle L matches up with angle C. They are the last letters of ABC and JKL

So angle L = 90 degrees as well

4 0

4 years ago

Read 2 more answers

How do you calculate the circumference of a sphere if you only have thd measurements of the diameter

Setler79 [48]

Hope it helps .

Step-by-step explanation:

Solve the equation for the diameter of the circle, d= C/π. In this example, "d = 12 / 3.14." or "The diameter is equal to twelve divided by 3.14." Divide the circumference by pi to get the answer.

7 0

4 years ago

Read 2 more answers

Each of ten tickets is marked with a different number from 1 to 10 and put in a box. If you draw a ticket from the box, what is

Tju [1.3M]

Answer:P(8)=1/10

The events are mutually exclusive so,

P(4 or 6 or 8)=P(4)+P(6)+P(8)=1/10+1/10+1/10=3/10.

6 0

3 years ago

A fair coin is tossed 10 times. The coin lands heads up all 10 times. What is the probability that it will land heads up on th

hoa [83]

It would be 50% if it is a fair coin

6 0

3 years ago

line m contains the points -3,4 and 1,0. write the equation of a line that would be perpendicular to this one and pass through t

castortr0y [4]

The equation of line perpendicular to line containing points (-3, 4) and (1, 0) and passes through (-2, 6) in point slope form is y = x + 8

<h3>Solution:</h3>

Given that line m contains points (-3, 4) and (1, 0)

We are asked to find the equation of line perpendicular to line containing points (-3, 4) and (1, 0) and passes through (-2, 6)

Let us first find slope of the line "m"

Given two points are (-3, 4) and (1, 0)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$\left(x_{1}, y_{1}\right)=(-3,4) \text { and }\left(x_{2}, y_{2}\right)=(1,0)$

$m=\frac{0-4}{1-(-3)}=-1$

Thus slope of line m is -1

We know that product of slope of given line and perpendicular line are always -1

So, we get

$\begin{array}{l}{\text { slope of line } m \times \text { slope of perpendicular line }=-1} \\\\ {-1 \times \text { slope of perpendicular line }=-1} \\\\ {\text { slope of perpendicular line }=1}\end{array}$

So we have got the slope of perpendicular line is 1 and it passes through (-2, 6)

Let us use the point slope form to find the required equation

The point slope form is given as:

$y - y_1 = m(x - x_1)$

$(x_1, y_1) = (-2, 6)$ and m = 1

y - 6 = 1(x - (-2))

y - 6 = x + 2

y = x + 8

Thus equation of required line in point slope form is y = x + 8

7 0

3 years ago