Question

Evaluate using identities( 3x+7) (3x +7)​

Answer 1

Answer:

$9 {x}^{2} + 42x + 49$

Explanation:

$(3x + 7)(3x + 7)$

$= > {(3x + 7)}^{2}$

Using the algebric identity${(a + b)}^{2} = {a}^{2} + {b + 2ab}^{2}$

So,

${(3x + 7)}^{2} = {(3x)}^{2} + {(7) }^{2} + 2 \times 3x \times 7$

$= 9 {x}^{2} + 42x + 49$