Answer:
The amplitude is 4 and the period is 2
Step-by-step explanation:
In the equation y = A sin (B x)
- A is the amplitude, where the amplitude is the height from highest to lowest points and divide the answer by 2
- The period is
, where the period is the distance from one peak to the next peak
∵ The equation is y = 4 sin(πФ)
- Compare it with form above
∴ A = 4 and B = π
∵ A is the amplitude
∴ The amplitude is 4
∵ Period =
∴ Period = ![\frac{2\pi }{\pi }](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpi%20%7D%7B%5Cpi%20%7D)
∴ Period = 2
∴ The period is 2
Answer:
Step-by-step explanation:
Side a = 16
Side y = 25.60535
Side x = 30.19328
Answer:
720 mins
Step-by-step explanation:
There are 60 mins in each hour. 12 x 60 is 720
Answer:
4 ohms
Step-by-step explanation:
The question is "In two minutes a current of 5 amps develops 1,200 heat units in a wire of 8 ohms resistance. What resistance does a similar wire have, which develops 6,000 heat units with a current of 10 amps in 5 minutes?"
Current, I₁ = 5 A
Heat, Q₁ = 1200 units
Resistance, R₁ = 8 ohms
Time, t₁ = 2 min = 120 s
New heat, Q₂ = 6000 units
Current, I₂ = 10 A
New time, t₂ = 5 min = 300 s
We need to find the new resistance.
Heat developed is given by :
![Q=I^2Rt](https://tex.z-dn.net/?f=Q%3DI%5E2Rt)
![\dfrac{Q_1}{I_1^2R_1t_1}=\dfrac{Q_2}{I_2^2R_2t_2}\\\\R_2=\dfrac{Q_2\times I_1^2R_1t_1}{Q_1I_2^2t_2}\\\\R_2=\dfrac{6000\times 5^2\times 8\times 120}{1200\times 10^2\times 300}\\\\=4\ \Omega](https://tex.z-dn.net/?f=%5Cdfrac%7BQ_1%7D%7BI_1%5E2R_1t_1%7D%3D%5Cdfrac%7BQ_2%7D%7BI_2%5E2R_2t_2%7D%5C%5C%5C%5CR_2%3D%5Cdfrac%7BQ_2%5Ctimes%20I_1%5E2R_1t_1%7D%7BQ_1I_2%5E2t_2%7D%5C%5C%5C%5CR_2%3D%5Cdfrac%7B6000%5Ctimes%205%5E2%5Ctimes%208%5Ctimes%20120%7D%7B1200%5Ctimes%2010%5E2%5Ctimes%20300%7D%5C%5C%5C%5C%3D4%5C%20%5COmega)
So, the new resistance is 4 ohms.
I'm not quite sure what this question means, but d = rt is a formula used to calculate the distance. the variables here are d for distance, r for rate, and t for time. if you need to solve it for t:
d = rt ... divide both sides by the rate (r)
(d/r) = t ... is your result