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Nady [450]
3 years ago
11

Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and

magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.
Mathematics
1 answer:
shusha [124]3 years ago
6 0
Forces in direction x:
 
fx1 = 100 * cos (50) = 64.28
 fx2 = 50 * cos (160) = - 46.99
 The resultant is:
 fx = fx1 + fx2 = 17.29

 Forces in direction y:
 
fy1 = 100 * sine (50) = 76.60
 fy2 = 50 * sine (160) = 17.10
 The resultant is:
 fy = fy1 + fy2 = 93.70
 The magnitude of the resulting force is:
 
f = root (fx ^ 2 + fy ^ 2)
 f = root ((17.29) ^ 2 + (93.70) ^ 2)
 f = 95.28
 The angle is:
 
theta = atan (fy / fx)
 theta = atan (93.70 / 17.29)
 theta = 79.55 degrees
 Answer:
 
The direction and magnitude of the resultant force are:
 
f = 95.28 pounds at theta = 79.55 degrees
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∠A ≅ ∠X

Step-by-step explanation:

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The length. l. of segment is given by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

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3 years ago
Read 2 more answers
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