Question

Obi Wan Kenobi is force pushing some bad guys into a forcefield. The bad guys (m= 300 kg) were originally at REST 5 meters away from the forcefield. It took them 0.5 seconds to hit the forcefield. How much force does Obi Wan apply?

Answer 1

Answer:

F = 12000 N = 12 KN

Explanation:

First we need to find the acceleration of the bad boys by using second equation of motion:

s = Vi t + (1/2)at²

where,

s = distance covered = 5 m

Vi = Initial Velocity = 0 m/s

t = time taken = 0.5 s

a = acceleration = ?

Therefore,

5 m = (0 m/s)(0.5 s) + (1/2)a(0.5 s)²

a = 2(5 m)/(0.5 s)²

a = 40 m/s²

Now, we calculate the force applied by Newton's Second Law:

F = ma

where,

F = force = ?

m = mass of bad guys = 300 kg

Therefore,

F = (300 kg)(40 m/s²)

F = 12000 N = 12 KN