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kupik [55]
3 years ago
15

Obi Wan Kenobi is force pushing some bad guys into a forcefield. The bad guys (m= 300 kg) were originally at REST 5 meters away

from the forcefield. It took them 0.5 seconds to hit the forcefield. How much force does Obi Wan apply?
Physics
1 answer:
rjkz [21]3 years ago
3 0

Answer:

F = 12000 N = 12 KN

Explanation:

First we need to find the acceleration of the bad boys by using second equation of motion:

s = Vi t + (1/2)at²

where,

s = distance covered = 5 m

Vi = Initial Velocity = 0 m/s

t = time taken = 0.5 s

a = acceleration = ?

Therefore,

5 m = (0 m/s)(0.5 s) + (1/2)a(0.5 s)²

a = 2(5 m)/(0.5 s)²

a = 40 m/s²

Now, we calculate the force applied by Newton's Second Law:

F = ma

where,

F = force = ?

m = mass of bad guys = 300 kg

Therefore,

F = (300 kg)(40 m/s²)

<u>F = 12000 N = 12 KN</u>

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A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.
ella [17]

Answer:

a. 17 μC b. 14.45 J

Explanation:

Here is the complete question

A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.

a. What charge is stored in each capacitor?

b. How much energy is stored in each capacitor?

a. The charge Q stored in a capacitor is Q = CV where C = capacitance  and V = voltage. Here, C = 10μF = 10 × 10⁻⁶ F and V = 1.7 kV = 1.7 × 10³ V.

So, Q = CV = 10 × 10⁻⁶ × 1.7 × 10³ = 1.7 × 10⁻² C = 17 × 10⁻³ C = 17 μC

b. The energy stored in a capacitor is given by W = 1/2CV² = 1/2 × 10 × 10⁻⁶ F × (1.7 × 10³ V)² =  1/2 × 10 × 10⁻⁶ F × 2.89 × 10⁶ V² = 1/2 × 10 × 2.89 × 10⁶ × 10⁻⁶ J = 14.45 J

8 0
3 years ago
Refrigerant 134a enters an air conditioner compressor at 4 bar, 20°C, and is compressed at steady state to 12 bar, 80°C. The vol
3241004551 [841]

Answer:

The magnitude of the heat transfer rate from the compressor is 87.05 kW

Explanation:

Initial pressure of refrigerant = 4 bar

Final pressure of refrigerant = 12 bar

From steam table,

Internal energy at 4 bar (U1) = 2554 kJ/kg

Internal energy at 12 bar (U2) = 2588 kJ/kg

Change in internal energy (∆U) = U2 - U1 = 2588 - 2554 = 34 kJ

Work input (W) = 120 kJ/kg

Quantity of heat transfer (Q) = ∆U + W = 34 + 120 = 154 kJ/kg

Volumetric flow rate of refrigerant = 8 m^3/min = 8/60 = 0.133 m^3/s

Density of refrigerant = 4.25 kg/m^3

Mass flow rate = density × volumetric flow rate = 4.25 kg/m^3 × 0.133 m^3/s = 0.56525 kg/s

Q = 154 kJ/kg × 0.56525 kg/s = 87.05 kJ/s = 87.05 kW

6 0
3 years ago
I need help with this
polet [3.4K]
Exothermic because the heat make part of the result
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Frequency is a measure of how many waves pass by in one second. <br> a. true <br> b. false
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True. Waves are measured in Hz. Wavelength is also measured in metres (m) - it is a length after all. The frequency, f, of a wave is the number of waves passing a point in a certain time. We normally use a time of one second, so this gives frequency the unit hertz (Hz), since one hertz is equal to one wave per second.
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Cold air can hold more moisture than warm air<br><br> true<br> false
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The answer is false

hope this helps
8 0
4 years ago
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