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seraphim [82]
3 years ago
15

4/x+3/x=14 A. 2 B. -2 C. 1/2 D. 3/7 E. 1/4​

Mathematics
1 answer:
Bess [88]3 years ago
4 0

Answer:

A. 2

you add 4x + 3x gives you 7x

then you divide by 7 on each side

7 divided by 7x is x

and 7 divided by 14 is 2

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Which expressions are equivalent to ln x 2 ln 5 ln 1? Check all that apply. 2 ln 5x ln (x 26) ln 25x ln 1 ln 25x.
Marysya12 [62]

Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.The expressions which are equivalent to the given expression are,

  • \ln25+\ln1
  • \ln25

Given information-

The expression given in the problem is,

\ln x+2 \ln 5 +\ln1

<h3>Equivalent expression-</h3>

Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.

For given expression,

\ln x+2 \ln 5 +\ln1

As the above function is the function of <em>x. </em>Thus it can be written as,

f(x)=\ln x+2 \ln 5 +\ln1

<h3>Logarithm power rule</h3>

Logarithm power rule states that the exponent of the logarithm function can transfers to front of the logarithm and vice versa. Thus,

f(x)=\ln x+ \ln 5^2 +\ln1\\&#10;f(x)=\ln x+ \ln 25 +\ln1

Now the value of \ln 1 is equal to the zero. Thus,

f(x)=0+\ln 25 +\ln1\\&#10;f(x)=0+\ln 25 +\ln1\\&#10;f(x)=\ln 25 +\ln1\\&#10;f(x)=\ln 25 +0\\&#10;f(x)=\ln 25

Hence the expressions which are equivalent to the given expression are,

  • \ln25+\ln1
  • \ln25

Learn more about the equivalent expression here;

brainly.com/question/10628562

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Write the rule to describe the translation.
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Step-by-step explanation:

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How are angles named?
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Acute angle, right angle, obtuse angle and reflex angle.

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4 0
3 years ago
Read the instructions
nordsb [41]

Answer:

Step-by-step explanation:

\frac{5x - 2}{4}+\frac{1}{2}=\frac{3y+2}{2}

Multiply the equation by 4

4*\frac{5x - 2}{4}+4*\frac{1}{2}=4*\frac{3y+2}{2}\\

5x - 2 + 2 = 2*(3y + 2)

5x +0 = 2*3y + 2*2

5x = 6y + 4

5x - 6y = 4 --------------------(I)

\frac{7y+3}{3}=\frac{x}{2}+\frac{7}{3}\\

Multiply the equation by 6

6*\frac{7y+3}{3}=6*\frac{x}{2}+6*\frac{7}{3}\\

2*(7y + 3) = 3x + 2*7

14y + 6 = 3x + 14

14y = 3x + 14 - 6

14y = 3x + 8

-3x + 14y = 8 ------------------------(II)

Multiply equation (I) by 3 and equation (II) by 5 and then add

(I)*3              15x - 18y = 12

(II)*5           <u>-15x  + 70y = 40</u>     {Now add}

                          52y = 52

                              y = 52/52

                            y = 1

Substitute y =1 in equation (I)

5x - 6*1 =  4

5x - 6 = 4

      5x = 4 +6

      5x = 10

         x = 10/5

x = 2

7 0
3 years ago
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