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2 years ago

Which functions graph has a y-intercept of 2?

Mathematics

1 answer:

jeka57 [31]2 years ago

6 0

Answer:

The y-intercept is the constant [whole number, the one without a variable] in the equation. So you're looking for the equation that has + 2 at the end, not -2.

Step-by-step explanation:

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Please help me answer this i need asap

damaskus [11]

Answer:24 xexponet 3 − 5

Step-by-step explanation:

4 0

2 years ago

Isolating a variable in two equations is easiest when one of them has a coefficient 1.

Tomtit [17]

Answer:

Option C.

Step-by-step explanation:

The given equations are

$3A-B=5$

$2A+3B=-4$

We need isolate one of the variables, such that it appears by itself on one side of the equation.

Isolating a variable in two equations is easiest when one of them has a coefficient 1.

In equation 1, coefficient of B is 1. So, we can easily isolate one of the variables.

The equation is

$3A-B=5$

Subtract 3A from both sides.

$-B=5-3A$

Multiply both sides by -1.

$B=3A-5$

Therefore, the correct option is C.

6 0

3 years ago

Help with this please. Thanks

nata0808 [166]

9514 1404 393

Answer:

3.0

Step-by-step explanation:

The angle, its opposite side, and the hypotenuse are given. Then the relevant trig relation is ...

Sin = Opposite/Hypotenuse

sin(21°) = x/8.3 . . . . . . . . . . . . . . . . . . use the given values

x = 8.3·sin(21°) ≈ 8.3×0.3584 . . . . . . multiply by 8.3

x ≈ 3.0

3 0

2 years ago

The following inequalities are equivalent except ...<br> A <3<br> B −1<2 C +1<3 D −2<1

Vlada [557]

Answer:

C + 1 < 3 is not equivalent.

Step-by-step explanation:

B - 1 < 2 ⇒ B < 3

C + 1 < 3 ⇒ C < 2

D - 2 < 1 ⇒ D < 3

Therefore, all inequalities are equivalent except C + 1 < 3.

5 0

2 years ago

Let D = {x| x is a student} be the domain, and let ƒ(x) = “date of birth” be the possible function. Determine if the relation is

Kazeer [188]

It is.

The function is just another way of saying to transfer something from domain A to domain B.

$f(x)=y:A\longrightarrow B; x\in A, y\in B$

Now your function states:

$D=\{x\} \\f(x)=y: D\longrightarrow E; x\in D, y\in E$

4 0

2 years ago