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bixtya [17]
3 years ago
14

How are sorting tools helpful for using spreadsheets and databases? Sorting tools let you locate information by searching for na

mes, numbers, or dates in search boxes. Sorting tools give you access to all the information in a spreadsheet so you can see everything at once. Sorting tools help you identify meaningful information and discard the data that are not valuable to your search. Sorting tools allow you to organize data into columns and rows that help you locate what you are looking for.
Computers and Technology
2 answers:
Serggg [28]3 years ago
8 0

Answer:

D on edge2020

Explanation:

Black_prince [1.1K]3 years ago
7 0

Answer:

Sorting tools allow you to organize data into columns and rows that help you locate what you are looking for.

Explanation:

Spreadsheet applications and relational databases are similar in configuration as they are both arranged in rows and columns (tabular). Sorting a spreadsheet or database is useful as it helps to organize data. A sorted spreadsheet or database can be in ascending or descending order which makes it easier and faster to locate rows of data manually or by query.

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When is the bond between the actin and myosin head is broken? when an ATP molecule binds to the myosin head when an ATP molecule
Goshia [24]

Answer:

The answer is when an ATP molecule binds to the myosin head.

Explanation:

when an ATP molecule binds to the myosin head. The molecule basis for this interaction is the binding of myosin to actin filaments, allowing the binding ATP dissociates myosin from actin.

8 0
3 years ago
Create a class named Console, and move all the methods that retrieve and validate user input to that class. These methods can re
otez555 [7]

Answer:

Here is the Console class:

import java.util.Scanner;  // to accept input from user

public class Console {   // class name

public Console() {}   //class constructor

public int getInt(Scanner sc, String prompt) { //gets user's number  

int i = 0;   //initialize i to 0

boolean isValid = false;   // checks for valid input

while (!isValid) {   //loop iterates as long as input remains valid

System.out.print(prompt);   //displays prompt

if (sc.hasNextInt()) {   // checks for the next token (input number)

i = sc.nextInt();   // scans and reads the next number

isValid = true;   // checks if input is valid

} else {   //if input is not valid

System.out.println("Error! Invalid integer value. Try again.");  }  //displays error message

sc.nextLine(); // discard any other data entered on the line   }

return i;  }  //returns number

public int getIntWithinRange(Scanner sc, String prompt, //checks users guess if outside parameters or not  

int min, int max) {  

int i = 0;  

boolean isValid = false;   //sets isValid to false

while (!isValid) {   //keeps iterating and stops when isValid is false

i = getInt(sc, prompt);   //calls getInt method to get users number

if (i <= min) {   //if number is less than value of min

System.out.println("Error! Number must be greater than " + min);   //displays this message

} else if (i >= max) {   //if number is greater than that of max

System.out.println("Error! Number must be less than " + max);   //displays this message

} else {   //if guess is right

isValid = true;   } } //sets isValid to true

return i;  } //returns that number

public  String getRequiredString(Scanner sc, String prompt) { //Asks for user's string input  

String s = "";  

boolean isValid = false;   //sets isValid to false

while (!isValid) {      //keeps iterating and stops when isValid is false

System.out.print(prompt);    //displays prompt

s = sc.nextLine();   //reads next line (read next string input value)

if (s.equals("")) {   //if user enters nothing

System.out.println("Error! This entry is required. Try again.");   //display this message

} else {   //if user enters a string input

isValid = true;   }  }  //sets isValid to true

return s; }  //returns string

public  String getChoiceString(Scanner sc, String prompt, //Checks for users input for Y/y ignores caps  

String s1, String s2) {

String s = "";  

boolean isValid = false;   //sets isValid to false

while (!isValid) {   //iterates until isValid is false

s = getRequiredString(sc, prompt);   //calls method to get the input string

if (!s.equalsIgnoreCase(s1) && !s.equalsIgnoreCase(s2)) {  // checks users input for Y/y ignores caps  

System.out.println("Error! Entry must be '" + s1 + "' or '" + s2 + "'. Try again.");   // displays error message that entry must be y or Y

} else {   //if user enters y or Y

isValid = true;   } }   //sets isValid to true

return s;  } } //returns y or Y

Explanation:

Here is the Game class

public class Game {  // class name

public Game() {}   //class constructor

public void displayWelcomeMessage() { //displays message  

System.out.println("Welcome to the Guess the Number Game");  

System.out.println("++++++++++++++++++++++++++++++++++++");  

System.out.println(); }

public  void displayPleaseGuessMessage() { //displays message for user to guess from 1-100  

System.out.println("I'm thinking of a number from 1 to 100.");  

System.out.println("Try to guess it.");  

System.out.println();}

public  void displayCorrectGuessMessage(int counter) { //display user's current guess count

System.out.println("You got it in " + counter + " tries.");  

if (counter <= 3) {   //if user guesses the number in 3 or less tries

System.out.println("Great work! You are a mathematical wizard.\n");  

} else if (counter > 3 && counter <= 7) {   //if user guesses the number greater than 3 but less than or equals to 7 tries

System.out.println("Not too bad! You've got some potential.\n");  

} else {   //if user guesses the number after more than 7 tries

System.out.println("What took you so long? Maybe you should take some lessons.\n"); }}

public  void displayGuessAgainMessage(int number, int guessNumber) { //Asks user to guess again  

int difference = guessNumber - number;  

if (guessNumber > number) {   //if guessNumber is greater than number

if (difference > 10) {   //if difference between guessNumber and number is greater than 10

System.out.println("Way too high! Guess again.\n");   //guessed number is higher than correct one

} else {  

System.out.println("Too high! Guess again.\n");  }

} else {  

if (difference < -10) {   //if difference between guessNumber and number is less than -10

System.out.println("Way to low! Guess again.\n");   //guessed number is lower than correct one

} else {  

System.out.println("Too low! Guess again.\n");}}}}

The main program and explanation of these above programs are given in the attached document.

The output of the program is attached.

3 0
3 years ago
Which statement describes the word "iterative"?
Umnica [9.8K]

guess you better read the directions and just read the book yourself and find the answer.

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Which of the following tips for using social network will help you keep your job
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Answer:

These are the best and most effective ways of using social media to get a job:

1.Share an online portfolio on social media.

2.Actively search for jobs on LinkedIn

3.Edit the privacy settings on your social media.

4.Engage in social media debates

5.Show your personality online.

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The LinkedIn Answers is a component of LinkedIn that allows you to get fast and accurate solutions to your questions. It provides a forum through which you can demonstrate your expertise by offering info to your network. You should use LinkedIn answers to ask and answer questions. Essentially, you should use it to provide examples to your work product, decision making skills, and on an interactive basis.






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