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9966 [12]
3 years ago
7

Pls help 23 points up for takeings

Mathematics
1 answer:
motikmotik3 years ago
3 0

Answer:

8x5=40 the 10 dollars

Step-by-step explanation:

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1.2 is it as a decimal or 0.5
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3 out of 4 students like to eat breakfast at school. What percent of students like to eat breakfast?
melomori [17]

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At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards
katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

v=t^2-5t+4 ,\, t\geq0

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

v

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t^2-5t+4

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(t-4)(t-1)=0

Zero Product Property:

t=1, \text{ and } t=4

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

v(0)=4>0,\, v(2)=-20

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0
3 years ago
PLease ANSWER You get 30 points On your math quiz, you earn 5 points for each question that you answer correctly. In the table b
Mamont248 [21]
The total number of points scored on the test woukd be 200. the independent variable would be x, or the number of questions answered correctly. the dependent would be the points scored because the points scored depends on how good you did on the test.
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Please help with this question!!
xxMikexx [17]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2\\\\l\perp k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\\text{We have the points J(-24, -4) and K(-4, 6)}.\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{substitute:}\\\\m_1=\dfrac{6-(-4)}{-4-(-24)}=\dfrac{10}{20}=\dfrac{1}{2}\\\\\text{therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2\\\\\text{The formula of a midpoint:}\\\\\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)\\\\\text{substitute the coordinates of the points J and K:}

x=\dfrac{-24+(-4)}{2}=\dfrac{-28}{2}=-14\\\\y=\dfrac{-4+6}{2}=\dfrac{2}{2}=1\\\\\text{midpoint}\ (-14,\ 1)\\\\\text{The point-slope form:}\\\\y-y_1=m(x-x_1)\\\\\text{substitute}\ m=-2,\ x_1=-14\ \text{and}\ y_1=1:\\\\y-1=-2(x-(-14))\\\\\boxed{y-1=-2(x+14)}

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