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adoni [48]
3 years ago
9

Determine,which is the better value 50 envelope for $2.49or 90 envelopes for$5.50

Mathematics
1 answer:
dusya [7]3 years ago
3 0

Answer:

50 envelopes for $2.49

Step-by-step explanation:

Option 1:

2.49/50 = 0.0498 per envelope

Option 2;

5.50/90 = 0.0611 per envelope

Option 1 is a better deal.

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Someone give me the answer????plz I’m really stuck and delayed on my homework answer this question and my other one I’ll give yo
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3 years ago
Find the value of x for which p is parallel to q, if m∠1 = (9x) and m∠3 = 117 .The diagram is not to scale.
kherson [118]
Oh I see sorry . My bad thinking!

m< 1 = m<3 ( corresponding angles) so

9x = 117 
x = 117 / 9  = 13

x = 13 Answer
3 0
3 years ago
Emma is planning her summer and would like to work enough to travel and buy a new laptop.
V125BC [204]
For the answer to the question above, <span>f x is the number of days she works, she'll earn $90x </span>
<span>After buying the laptop, she'll have $90x - $700 left over, which will pay for ($90x - $700) / $150 days of travel. So we have y = ($90x - $700) / $150 = (9x - 70) / 15 = 0.6x - (14/3) </span>
<span>Note that y can't be negative. Also, if y = 0, then Emma doesn't get to travel at all, so we should avoid that. So we have: </span>
<span>0.6x - (14/3) > 0 </span>
<span>0.6x > 14/3 </span>
<span>x > (14/3) / 0.6 </span>
<span>x > 70/9 </span>
<span>The question says that x can be up to 40, so the domain is 70/9 < x <= 40 </span>
<span>That's approximately 7.777... < x <= 40 </span>
<span>Multiply those numbers by 0.6 and then subtract 700 to get the range: </span>
<span>0 < y <= 58/3 </span>
<span>That's approximately 0 < y <= 19.333</span>
3 0
3 years ago
Read 2 more answers
How do you change a mixed number to a decimal?
Alina [70]
You put a . so say 5034 it would be 50.34
6 0
3 years ago
Estimate the sum of the decimals below by rounding each summand to the
Dimas [21]

Answer:

18

Step-by-step explanation:

8.355 rounds to 8

1.533 rounds to 2

8.260 rounds to 8

8 + 2 + 8 = 18

7 0
3 years ago
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