Question

Given the rational function below and it’s graph, explain why there is a “hole” in the graph at x=2 hints: are there any inputs that are undefined? Can you factor the numerator? Does it simplify? Does it tell you why this graphs as a line?

Answer 1

Answer:

Step-by-step explanation:

Given function is, $f(x)=\frac{x^2-3x+2}{x-2}$

Factors of the numerator = x² - 3x + 2

                                          = x² - 2x - x + 2

                                          = x(x - 2) - 1(x - 2)

                                          = (x - 2)(x - 1)

Therefore, given function will be,

f(x) = $\frac{(x-2)(x-1)}{(x-2)}$

For (x - 2) = 0

For x = 2, denominator will become zero.

Thus for input value x = 2, function will not be defined.

If x ≠ 2, f(x) = x - 1

It's a linear function represented by f(x) = x - 1

Having slope = 1 and y-intercept = -1

And (2, 1) is a hole as shown in the graph.