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Georgia [21]
3 years ago
12

Which statement about the ordered pairs (2, −9) and (3, −6) is true for the equation 5x−y3=13 ?

Mathematics
2 answers:
Hatshy [7]3 years ago
5 0
C is correct..........
pentagon [3]3 years ago
4 0

Answer:

THe aNSweR Is...

Step-by-step explanation: NeiTHeR orDerEd PaiR iS a sOLutIoN.


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melomori [17]

Answer:

A = pi/3 = 1.05°

Step-by-step explanation:

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2 years ago
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Anya bought some cans of paint. She used 9 of them to
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7 0
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3 0
3 years ago
of the 75 boys in the 7th grade class, 25 participate in at least one sport . of the 120 girls in 7th grade class 30
hoa [83]

Answer:

"No, the relationship is NOT proportional"

Step-by-step explanation:

<u>Complete Question:</u>

Of the 75 boys in the 7th grade class, 25 participate in at least one sport. Of the 120 girls in 7th grade class 30 participate in at least one sport. Is this relationship proportional?

We have to see the ratio of each and if they are equal (after reducing), we can say they are proportional.

Boys:

25 participate in atleast 1 sport and there are total of 75. Hence, ratio is

25 : 75 = 1 : 3

Girls:

30 particiapte in atleast 1 sport and there are toal of 120. hence ratio is:

30 : 120 = 1 : 4

So, the relationship is NOT proportional

6 0
2 years ago
Find the term indecent of x in the expansion of (x^2-1/x)^6
Mars2501 [29]

By the binomial theorem,

\displaystyle \left(x^2-\frac1x\right)^6 = \sum_{k=0}^6 \binom 6k (x^2)^{6-k} \left(-\frac1x\right)^k = \sum_{k=0}^6 \binom 6k (-1)^k x^{12-3k}

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0   ===>   3k = 12   ===>   k = 4

which corresponds to the constant coefficient

\dbinom 64 (-1)^4 = \dfrac{6!}{4!(6-4)!} = \boxed{15}

3 0
2 years ago
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