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svp [43]
3 years ago
12

Triangle PQR is similar to triangle XYZ. The length of PQ is one-half the length of XY. THe length of RP is 2 cm. Which proporti

on can be used to find the length of ZX?
Mathematics
1 answer:
e-lub [12.9K]3 years ago
5 0

Answer:

ZX = 4cm

Step-by-step explanation:

Given

\triangle PQR similar to \triangle XYZ

PQ = \frac{1}{2}XY

RP = 2cm

Required

Find ZX

\triangle PQR similar to \triangle XYZ implies that, the following sides are similar

PQ \to XY

QR \to YZ

RP \to ZX

To find ZX, we make use of the following equivalent ratio

PQ : XY = RP : ZX

Where

PQ = \frac{1}{2}XY

RP = 2cm

So, we have:

\frac{1}{2}XY : XY = 2cm : ZX

Express as fraction

\frac{\frac{1}{2}XY }{ XY }= \frac{2cm }{ ZX}

\frac{1}{2}= \frac{2cm }{ ZX}

Make ZX the subject

ZX = 2 * 2cm

ZX = 4cm

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I need help ASAP <br><br><br> -2x^2+x<br><br> 9-25x^2+8x<br><br> X^5+x^3-x^2-1
nika2105 [10]

Answer:

For -2x^2+x, Leading coefficient is -2, Degree is 2, Constant term is 0

For 9-25x^2+8x, Leading coefficient is -25, Degree is 2, Constant term is 9

For x^5+x^3-x^2-1, Leading coefficient is 1, Degree is 5, Constant term is -1

Step-by-step explanation:

Given:

Polynomials:

-2x^2+x\\9-25x^2+8x\\x^5+x^3-x^2-1

To find: leading coefficient, constant term and degree

Solution:

Leading coefficient is the coefficient of the variable with the highest power.

Degree is the highest power of the variable.

The term of degree 0 is the constant term of a polynomial.

For -2x^2+x,

Leading coefficient is -2

Degree is 2

Constant term is 0

For 9-25x^2+8x

Leading coefficient is -25

Degree is 2

Constant term is 9

For x^5+x^3-x^2-1

Leading coefficient is 1

Degree is 5

Constant term is -1

4 0
4 years ago
PLEASE HELP IM DESPERATE!!!!
Lynna [10]

Answer:

2%

Step-by-step explanation:

Let x be the first number

It increases by 70 %

The new number is

m = x+ .70x

   = 1.7x

Let y be the second number

It decreases by 40 %

The new number is

n =y - .40 y

  = .6y


The product of the original numbers is xy

The product of the new number is

mn = (1.7x * .6y) = 1.02xy

The new number is larger than the old number so it is an increase.

Percent increase is  new - original divided by original  times 100%

Percent increase = (1.02 xy - xy)

                                -----------------  * 100%

                                 xy  

                           = .02 xy

                                ------- * 100 %

                                 xy  

                            = .02 * 100 %

                             = 2%


7 0
3 years ago
given the following information, determine which lines, if any, are parallel. state the converse that justifies your answer.
frozen [14]

From the information in the diagram found in a similar question online (please see attached drawing), the parallel lines are;

  1. w||z
  2. x||y
  3. x||y
  4. w||z
  5. w||z
  6. x||y
  7. x||y
  8. w||z
  9. x||y
  10. w||z

<h3>What are the relationships between angles formed by parallel lines?</h3>

Parallel lines are lines that do not meet, when extended indefinitely.

The possible information given as obtained from a similar question posted online are;

1. ‹1 is congruent to ‹5

2. ‹7 is congruent to ‹9

3. m‹8 + m‹9 = 180°

4. ‹16 is congruent to ‹14

5. m‹1 + m‹4 = 180°

6. ‹3 is congruent to ‹13

7. ‹2 is congruent to ‹10

8. ‹11 is congruent to ‹15

9. m‹4 + m‹13 = 180°

10. ‹8 is congruent to ‹6

1. Given that ‹1 is congruent to ‹5 where ‹1 and ‹5 are alternate exterior angles, we have that line <em>w </em>is parallel to line <em>z </em>

  • w||z

Theorem (converse); Alternate exterior angles formed by two parallel lines having a common transversal are congruent.

2. ‹7 and ‹9 are alternate interior angles.

Given that ‹7 is congruent to ‹9, therefore;

Line <em>x</em> is parallel to line <em>y</em>

  • x||y

Theorem (converse); Alternate interior angles formed by two parallel lines having a common transversal are congruent.

3. Given that m‹8 + m‹9 = 180°, therefore;

‹8 and ‹9 are supplementary angles, formed between lines <em>x </em>and <em>y</em>.

‹8 and ‹9 are also consecutive interior angles.

Theorem (converse); Consecutive interior angles formed between parallel lines are supplementary.

Therefore;

  • x||y

4. ‹16 and ‹14 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Corresponding angles formed by parallel lines are congruent.

Given ‹16 congruent to ‹14, we have;

  • w||z

5. m‹1 and m‹4 are consecutive exterior angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Consecutive exterior angles formed by two parallel lines are supplementary.

Given that m‹1 + m‹4 = 180°, we have;

  • w||z

6. ‹3 and ‹13 are alternate exterior angles formed by lines <em>x </em>and <em>y</em>.

Theorem (converse); Alternate exterior angles formed by parallel lines are congruent.

Given that ‹3 congruent to ‹13, we have;

  • x||y

7. ‹2 and ‹10 are corresponding angles formed by lines <em>x </em>and <em>y</em>

Given that ‹2 congruent to ‹10, therefore;

  • x||y

8. ‹11 and ‹15 are alternate interior angles formed by lines <em>w </em>and <em>z</em>.

‹11 is congruent to ‹15, therefore;

  • w||z

9. ‹4 and ‹13 are consecutive exterior angles formed by lines <em>x </em>and <em>y</em>

m‹4 + m‹13 = 180°, therefore;

  • x||y

10. ‹8 and ‹6 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

‹8 is congruent to ‹6, therefore;

  • w||z

Learn more about angles formed by parallel lines that have a common transversal here:

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