Since the box will move only in the horizontal direction and no net vertical motion then the force for the horizontal motion is equal to fcos θ. then this force is equal to the normal force and friction force exerted by the floor.fcos θ = us (Mg + fsin θ)fcos θ = us Mg + us fsin θfcos θ - us fsin θ = us Mgf(cos θ - us sin θ) = us mgf = us Mg/ (cos θ - us sin θ)
Answer:
Comprimento: 28.9 m; Largura: 11.1 m
Step-by-step explanation:
P = 2(C + L) = 80
A = CL = 320
2(C + L) = 80
CL = 320
C + L = 40
CL = 320
C = 40 - L
CL = 320
(40 - L)L = 320
40L - L^2 = 320
L^2 - 40L + 320 = 0
aL^2 + bL + c = 0
or
L = 28.9
C = 40 - L = 40 - 28.9 = 11.1
Answer: Comprimento: 28.9 m; Largura: 11.1 m
The height of the cone is 4 cm (approx).
Step-by-step explanation:
Given,
The radius (r) of the cone = 4.96 cm
Volume (V) = 102 cm³
To find the height (h) of the cone.
Formula
The volume of a cone V = πr²h
Now,
According to the problem,
πr²h = 102
or, ××(4.96)²h= 102
or, h =
or, h = 3.95 = 4 (approx)
so,
Height = 4 cm (approx)
Answer:
— 3n−30=3+n.
Step-by-step explanation:
The second one, fourth one, and the fifth one