Answer:
A sample size of 385 is needed.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.96.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
You feel that a reasonable estimate of the standard deviation is 10.0 hours.
This means that 
What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?
A sample size of n is needed. n is found when M = 1. So





Rounding up:
A sample size of 385 is needed.
Answer:
Convert the improper fraction into a mixed number:dfrac2 * 2 + 12 / 5/8 Calculate the product or quo.
Step-by-step explanation:
It’s the second one x>_12 because it’s a closed circle on the number line and it’s going right
Answer:
This question is incomplete. What exactly are we doing to the equation
PS; You can answer in the comment section. I'd help out there
Answer: welp im in 7th grade so uh... i may be underqualified... but here's my attempt! if it's wrong just lmk and I'll delete it
In the owl world egg laying usually happens about one month after courtship begins. The incubation period for owl eggs is about 30 days, so taking 2 months to increase population is about normal.
Step-by-step explanation: sorry if it's wrong