Solution:
Consider numbers which are Squares,cubes, fourths, fifths of some natural numbers.
For example, Starting from squares of some natural number: 4,9,16,25,36,49,64......
and their factors , which are 4= 1 × 2×1×2
9=1×3×1×3
16=2×1×2×1×2×1×2×1
25=1×5×1×5
36=2×3×2×3
64=2×4×2×4
Now coming to cubic numbers
8= 1 ×2×1×2×1×2
27= 1×3×1×3×1×3
3125= 3 ×5×3×5×3×5
So,the numbers whose factor pairs repeats are square, cubic, fourth,Fifth ,Sixth and.....higher powers of natural Numbers.
→→→So, we just need to check that whether those numbers whose factor pairs repeats are Squares, cubes or higher powers of natural numbers.
Answer:
n^2+2n+1
Step-by-step explanation:
-2-8-18-32-50
difference=-6-10-14-18
common differences=-4-4-4-4-4
-2-8-18-32-50
n^2=1,4,9,16,25
minus it
=-1,-4,-9,-16,-25
differences 2,5,7,9
common differences=2
2,4,6,8
so 2n+1
so the answer is n^2+2n+1
The answer is A in my opinion
The answer to ur math question is 78
Answer:
2 weekend days and 4 weekday days
Step-by-step explanation:
12 x 2 = 24
7 x 4 = 28
28 + 24 = 52