Write a polynomial function f of least degree that has a leading coefficient of 1 and given zeros 3, 2

The sum of two angle measures 130 degrees. The difference in the two angle measures is 12 degrees. What are the two angle measur

san4es73 [151]

Answer:

59°, 71°

Step-by-step explanation:

This is a "sum and difference" problem. All problems of this type have the same answer: the larger of the two numbers is the average of those given.

Then the larger angle is (130 +12)°/2 = 71°. The smaller is 71° -12° = 59°.

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More detailed solution

There are several ways to get there using equations. You can, for example, let L represent the larger number. Then L - D will be the smaller one (where D represent the difference). The sum of the two numbers (S) is ...

L + (L -D) = S

2L = S + D . . . . collect terms, add D

L = (S+D)/2 . . . the larger number is the average of the sum and difference

5 0

3 years ago

What is the value of y when line m is parallel to line n

leonid [27]

Quick Check: Review of Parallel and Perpendicular Lines

1. B. angle 4
2. B. alternate interior angles
3. D. 150
4. D. a = 36, b = 118, c = 62

8 0

3 years ago

3 over 5 times 7 over 12

hoa [83]

Answer:

0.35

Step-by-step explanation:

3 over 5 = 0.6

0.6 times 7 = 4.2

4.2 over 12 = 0.35

6 0

3 years ago

(a) Complete the table of values for y = 6 - 4x. Please help ❤️

shutvik [7]

Answer:

$\boxed{\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}}$

Step-by-step explanation:

Given equation to us is :-

$\implies y = 6 - 4x$

So , here we can put different values of x in order to get different values of y .

Initial table given to us is ,

$\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & & & 2&&-6 \\\cline{1-6}\end{tabular}$

Put x = (-1) :-

$\implies y = 6 - 4x \\\\\implies y = 6 -4(-1) \\\\\implies y = 6 + 4 \\\\\red{\bf\implies y = 10}$

Put x = 0 :-

$\implies y = 6 - 4x \\\\\implies y = 6-4(0) \\\\\implies y = 6 - 0 \\\\\pink{\bf\implies y = 6 }$

Put x = 2 :-

$\implies y = 6-4x \\\\\implies y = 6 - 4(2) \\\\\implies y = 6 - 8 \\\\\blue{\bf\implies y = (-2)}$

Hence the final table would be :- 

$\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}$

4 0

3 years ago

Please help with geometry will mark branliest!

scoray [572]

x = 2

given 2 secants from an external point then

Then the product of the external part and the entire secant equals the product of the external part and the entire secant of the other secant.

3 ( 3 + 5 ) = 4 (4 + x )

3 × 8 = 4 ( 4 + x ) ⇒ 24 = 4 ( 4 + x )

divide both sides by 4

6 = 4 + x ⇒ x = 6 - 4 = 2

4 0

3 years ago