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4 years ago

Round 84. 359 to the nearest tenth.

Mathematics

1 answer:

natka813 [3]4 years ago

7 0

Answer: 84. 4

Step-by-step explanation:

Since the number next to the tenths place is the number 5 or above, you round the 3 up to a 4 in the 10ths place.

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Which expression is eqivilent to 4.8 +2.2w - 1.4w + 2.4

yan [13]

Answer:

kmjnhbgvfcdxszxcvgbhnjmk,lkjhgfd

Step-by-step explanation:

8 0

3 years ago

Please answer the question in the photo, thanks!

belka [17]

Answer:

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right )$

We rearrange the fractions as improper fractions for easier division as follows;

$2\dfrac{1}{3} = \dfrac{7}{3}$

$-3\dfrac{2}{3} = -\dfrac{11}{3}$

Therefore, we have;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}$

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

4 0

3 years ago

The selling price of an item is $650. It is marked down by %10, but this sale price is still marked up from the cost of $450.

Hoochie [10]

Answer:

nothing

Step-by-step explanation:

You get nothing because it would make -43256742984

7 0

3 years ago

Read 2 more answers

Please help please help please help please help please help please help please help please help

Burka [1]

I Believe it’s the first one

5 0

3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago

Round 84. 359 to the nearest tenth. ​

Round 84. 359 to the nearest tenth.