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Margarita [4]
3 years ago
10

Anyone know how to do??

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer:

Remove question mark and add a 5

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Determine the perimeter of triangle AGN.
Harman [31]

Answer:

150

Step-by-step explanation:

The perimeter of a triangle is defined or given as the summation of all its 3 sides.

Mathematically,

The perimeter of a Triangle = Side A + Side B + Side C

In the above question, we are to find the perimeter of Triangle AGN.

In the diagram , we have an inscribed circle of RTE

Therefore these values are given in the question.

Side AR = 35

Side RG = 21

Side EN = 19

We have an inscribed Triangle in the question with its side touching the Triangle. This means we have lines that are tangent. Hence we have,

Side EG = Side RG = 21

Side TN = Side EN = 19

Side AT = Side AR = 35.

Therefore, The Perimeter of Triangle AGN = Side AT + Side AR + Side TN + Side EN + Side EG + Side RG

= 35 + 35 + 19 + 19 + 21 + 21

= 150

The perimeter of Triangle AGN is 150

3 0
4 years ago
A dance class consists of 22 students, of which 10 are women and 12 are men. if 5 men and 5 women are to be chosen and then pair
OverLord2011 [107]

solution:

I choose 5 women from a pool of 10 in 10C2 ways.

I choose 5 men from a pool of 12 in 12C2 ways.

So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.

But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!

So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.

3 0
4 years ago
Given the rectangle abcd shown below has a total area of 72. E is in the midpoint of bc and f is the midpoint of dc. What is the
scoray [572]

Refer to the attached image.

Given the rectangle ABCD of length 'l' and height 'h'.

Therefore, CD=AB = 'l' and BC = AD = 'h'

We have to determine the area of triangle AEF.

Area of triangle AEF = Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

Area of triangle ADF = \frac{1}{2}bh

= \frac{1}{2}(DF \times AD)

= \frac{1}{2}(\frac{l}{2} \times h)

=\frac{lh}{4}

Area of triangle ECF = \frac{1}{2}bh

= \frac{1}{2}(CF \times CE)

= \frac{1}{2}(\frac{l}{2} \times \frac{h}{2})

=\frac{lh}{8}

Area of triangle ABE = \frac{1}{2}bh

= \frac{1}{2}(AB \times BE)

= \frac{1}{2}(l \times \frac{h}{2})

=\frac{lh}{4}

Now, area of triangle AEF =

Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

= 72 - (\frac{lh}{4} + \frac{lh}{8} + \frac{lh}{4})

= 72 - (\frac{2lh+lh+2lh}{8})

=72 - (\frac{5lh}{8})

=72 - (\frac{5 \times 72}{8})

=\frac{72 \times 8 - (5 \times 72)}{8}

= 27 units

Therefore, the area of triangle AEF is 27 units.

8 0
3 years ago
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. Supp
Trava [24]

Answer:

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

Step-by-step explanation:

As the test is targeted to 18-to-29-year-old adults using  social media, we want to know the probability that a randomly selected adult uses social media and belong to the study group.

To achieve this, we have this data:

- 36% of all adults do not use social media

- 75% of all adults are >30 years old.

- The percentage of population that is <em>either</em> 18-29 years old <em>or</em> uses social media is 66.7%

Using the last data we have that

P(social\,media=yes\, or\,18-29=yes)=P(social\,media=yes)+P(18-29=yes)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=(1-0.36)+(1-0.75)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=0.64+0.25-P(social\,media=yes\, \&\,18-29=yes)\\\\P(social\,media=yes\, \&\,18-29=yes)=0.64+0.25-0.667=0.223

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

8 0
3 years ago
Emergency!!!! Please help Geometry
Kobotan [32]
D. 1 3/4 min
When you go on a Ferris wheel you go up then down in a circular motion.
5 0
3 years ago
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