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zepelin [54]
3 years ago
5

The depth of a pond changes from 8 2/5 m to 5 1/2 m over a period of 1 2/3 mo.

Mathematics
1 answer:
g100num [7]3 years ago
7 0

Answer:

Step-by-step explanation:4767

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6 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
Please help with this​
dexar [7]

Answer:

13) 1,11      14) 1,2,11,22    15) 1, 2, 4, 7, 14, 28      16) 1, 2, 4, 8, 16, 32           17) 1, 2, 3, 6, 7, 14, 21, 42

Step-by-step explanation:

5 0
2 years ago
IThere are 5 times as many males as females on the maths course at university. What fraction of the course are male? Give your a
melomori [17]

Answer:5/1

Step-by-step explanation:5 times 1 is 5 so for every female it’s 5 male

6 0
3 years ago
Please solve for y need ASAP
MrMuchimi
6(y+2) = 4(z+9)
6y + 12 = 4z + 36
6y = 4z + 24
  y = (4z + 24) / 6
  y = (2z + 12) / 3

answer
C.  y = (2z + 12)/3
7 0
3 years ago
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