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3 years ago

21 is less than w+6 solve the inequality for w

Mathematics

2 answers:

OLEGan [10]3 years ago

7 0

Answer:

15 < w

Step-by-step explanation:

We are given the expression "21 is less than w + 6" and are asked to solve this inequality for "w".

To do so, we first need to create the actual inequality, if 21 is less than w + 6, then the sign we should use is the less than sign (<).

21 < w + 6

Now we solve for w, which is by isolating w :

21 < w + 6

Subtract 6 from both sides :

15 < w

Aleksandr [31]3 years ago

6 0

Step-by-step explanation:

21<w+6

honestly I think im wrong because I didn't really get the question, sorry

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4+2(8²×4²)+6+4+6+6+6+2+2

mash [69]

Answer: =2084

4+2(82)(42)+6+4+6+6+6+2+2

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4 0

3 years ago

Read 2 more answers

What are the solutions to the equation 3(x – 4)(x + 5) = 0

Ne4ueva [31]

Answer:

x=4

x=-5

Step-by-step explanation:

in order for this to be equal to 0, 1 or both of the factors has to be 0, because anything multiplied by 0 is 0.

123 * 29382 * 8139* 0 = 0

x-4 = 0

x = 4

x+5 = 0

x=-5

7 0

2 years ago

The diagram shows a right-angled triangle.

goldfiish [28.3K]

Answer:

Step-by-step explanation:

Ac²= AB²+ BC²

Ac²= 4²+15²= 16+225

Square both side

Ac = √241= 15.52cm

8 0

2 years ago

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

4 0

3 years ago

find the total surface area of the following cuboids length=7cm,breadth=4cm,height=3cm please help me with this problem.help me

Zielflug [23.3K]

Answer:

122

Step-by-step explanation:

SA=2lw+2lh+2hw

SA = 2(7)(4) + 2(7)(3) + 2(3)(4)

SA = 122

8 0

2 years ago