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3 years ago

12

A pitcher contains 40 fluid ounces of iced tea. Shelby pours 3 cups of iced tea .How many pints of iced tea are left in the pitc

her

2 answers:

tatiyna3 years ago

6 0

Answer:

Step-by-step explanation:

3

aliina [53]3 years ago

3 0

Answer:

1 pint is left

Step-by-step explanation:

3 cups=24 ounces

40-24=16

16 ounces= 1 pint

Plz give me Brainliest

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Which number is between 7.17 x 10^4 and 8.17 10^5 A. 6.92 x 10^4 B. 7.2 x10^9 C. 7.57 x 10^3 D. 8.053 x 10^4

Serga [27]

Answer:

D. 8.053 x 10^4

Step-by-step explanation:

Given :

7.17 x 10^4 and 8.17 10^5

The number in between the two Given numbers should be greater Than 7.17*10^4 but less than 8.17*10^5

A. 6.92 x 10^4 - this is less than 7.17 * 10^4 ; hence doesn't fit in

B. 7.2 x10^9 - this is greater than both values, hence, doesn't fit in

C. 7.57 x 10^3 - this is less than 7.17*10^4 ; hence does not fit in

D. 8.053 x 10^4 - this fits in as it is greater than 7.17*10^4 and less than 8.17*10^5 ; hence, it is the correct answer.

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3 years ago

A supermarket sells two flavors of cereal: a fruit flavor and a chocolate flavor. In a market survey, the event that a customer

Sedaia [141]

This is a binomial distribution.
p = 0.71, q = 1 - p = 1 - 0.71 = 0.29, n = 20

P(x ≤ 19) =1 - P(x = 20) = 1- 20C20 x (0.71)^(20 - 20) x (0.29)^20 = 1 - 0.29^20 = 1 - 0 = 1

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3 years ago

A + (b + c) = (A + b) + c<br><br><br> What property is this equation

Free_Kalibri [48]

Answer:

Step-by-step explanation:

Associative property

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3 years ago

A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas

WITCHER [35]

Answer:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

$P(A) = 0.8, P(B) = 0.2$

We are assuming that the two events are independent so then we have the following propert:

$P(A \cap B ) = P(A) * P(B)$

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

$P(B' \cup A')$

And using the De Morgan laws we know that:

$(A \cap B)' = A' \cup B'$

So then we can write the probability like this:

$P(B' \cup A') = P((A \cap B)')$

And using the complement rule we can do this:

$P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)$

Since A and B are independent we have:

$P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32$

And then our final answer would be:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

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3 years ago

Can someone help me .

RUDIKE [14]

Answer:

b part is the correct answer

3 0

2 years ago