Answer:
Age of Anna = x years
Age of Jane i.e. Anna's sister = (x-y) years
a, What was the sum of their ages two years ago?
Solution,
Age of Anna two years ago = (x-2) years
Age of Jane two years ago = (x-y-2) years
Sum of their ages = x - 2 + x-y-2 = 2x - y -4
b. What will be the sum of their ages in 3 years?
Solution,
We have,
Present age of Anna = x years
Present age of Jane = (x-y) years
So,
Age of Anna after 3 years = (x+3) years
Age of Jane after 3 years = (x-y+3) years
Therefore,
Sum of their ages in 3 years = (x+3) +(x-y+3) = 2x - y+6
c. How old was Anna when Jane was born?
Solution,
Here,
According to question,
Jane is y years younger than Anna
So, Anna was y years when Jane was born.
[Suppose your age is 10 years and your brothers age is 14 years. You are 4 years younger than your brother. Also, his age was 4 years when you were born.]
X = (L + 2k)/(x - b). You have the correct answer selected
which is Marcella's age
of 63 is 21 ⇔ 63÷3=21
which is Justins age
Marcella's age⇒63
Justin's age⇒23
Aimee's age⇒42
Note: I was trying to find a better way to do this but I couldn't figure it out in the top of my head so I'm sorry for the long response
Answer:
The function which represents this sequence will be:
Hence, option (A) is true.
Step-by-step explanation:
Given the sequence
An arithmetic sequence has a constant difference 'd' and is defined by
computing the differences of all the adjacent terms
As the difference is the same, so
as
Thus, substituting , in the nth term of an arithmetic sequence
Therefore, the function which represents this sequence will be:
Hence, option (A) is true.