1) b=1
-3+1=3b-5
Add 3b to both sides.
1=6b-5
Add 5 to both sides
6=6b
Divide both sides by 6
b=1
2) t=11
(1/2)t+7=(3/2)t-4
Subtract 1/2t from both sides.
7=t-4
Add 4 to both sides.
t=11
3) x=-0.878
-2.3 +1.2x=5.9-2.9x
Subtract 1.2x from both sides
-2.3=5.9-4.1x
Add 5.9 to both sides.
3.6=-4.1x
Divide by -4.1
x=-0.878
4)No solution
-7y-21=-3y-21
Add 3y to both sides.
-4y-21=-21
Add 21 to both sides
-4y=0
29
Note that consecutive numbers have a difference of 1 between them.
let n be the smallest integer then the three integers can be expressed as
n, n + 1 , n + 2
the sum is then
n + n + 1 + n + 2 = 90
3n + 3 = 90
subtract 3 from both sides of the equation
3n = 90 - 3 = 87
divide both sides by 3
n =
= 29
the three integers are 29, 30, 31 → the smallest is 29
First add y on both sides to get x = y-8, then add 8 on both sides to get x + 8 = y. thats really all you can do because you don't have the slope, so it ends up being y = mx+8
May we have details so we know how to answer