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makvit [3.9K]
3 years ago
6

Greg invested $9,000 in an investment account that earns 4.2% interest compounded monthly.

Mathematics
1 answer:
Ulleksa [173]3 years ago
6 0

Answer:

Step-by-step explanation:

y=a(1+r/c)^{ct}\\ \\ y=9000(1+.042/12)^{12t}\\ \\ y=9000(1.0035)^{12t}\\ \\ a)\ y=9000(1.0035)^{12(10)}=\$ 13687.61\\ \\ b)\ 15400=9000(1.0035)^{12t}\\ \\ 1.0035^{12t}=77/45\\ \\ 12t ln(1.0035)=ln(77/45)\\ \\ t=(ln(77/45))/(12ln(1.0035))\\ \\ t\approx 12.8\ years

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The percentage profit earned by selling a watch for Nu 1920 is equal to the percent loss incurred by selling the same watch for
dimaraw [331]

Answer:

2,000

Step-by-step explanation:

The computation of the price that should be sold for making 25% profit is shown below:

Let cost price be x

Now the equation would be

(1,920 - x) ÷ x × 100 = (x - 1,280) ÷ x × 100

1,920 - x = x - 1,280

2x = 3,200

x = 1,600

Now the sale price would be

= 1,600 × 1.25

= 2,000

6 0
3 years ago
you can work no more than 20 hours next week. you need to earn at least $92 to cover you weekly expenses. your dog-walking job p
Xelga [282]
Work 12-hour dog walking  work and work 5 hours as a car wash attendant

This will give 92$
5 0
4 years ago
Find the value of x 117,145,133,140,119,125
andreev551 [17]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Is this a function ?
Goshia [24]
I don’t think so, a graph is a function only if the vertical line passes through the graph at one distinct point.

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6 0
3 years ago
Which set of ordered pairs could represent a function? (2, 3), (2, 2), (2, 4), (2, 9), (2, –2) (1, 5), (2, 6), (1, 6), (4, 5), (
Ratling [72]

Given:

The set of ordered pairs in the options:

(a) (2, 3), (2, 2), (2, 4), (2, 9), (2, –2)

(b) (1, 5), (2, 6), (1, 6), (4, 5), (1, 4)

(c) (1, 0), (2, 0), (1, 3), (4, 3), (5, 7)

(d) (5, 1), (7, 3), (9, 5), (11, 7), (13, 9)

To find:

The set of ordered pairs that could represent a function.

Solution:

A set of ordered pairs represent a function, if there exist unique output (y-value) for each input (x-value).

In option (a) we have, five output values y=3,2,4,9,-2 for single input x=2. So, it is not a function.

In option (b) we have, three output values y=5,6,4 for single input x=1. So, it is not a function.

In option (c) we have, two output values y=0,3 for single input x=1. So, it is not a function.

In option (d), all inputs has unique output.

Therefore, the correct option is (d).

4 0
3 years ago
Read 2 more answers
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