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2 years ago

Number of stickers is less than 1145 but greater than 1100. How many stickers?

Mathematics

1 answer:

dimaraw [331]2 years ago

5 0

45 stickers because 1145 - 1100 = 45.

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A school principal has to choose randomly among the six best students in each grade to be the school captain every month. For th

frez [133]

Answer: b. It's a fair method because each result is an equally likely possible outcome.

The number of students is same as the number of the sides of the dice. In this scenario, the school principal will roll two dices three times and the number that repeated most will be chosen. For every dice, all number will have equally likely possibility so the randomization is fair(1/6 chance for every student).Rolling the dice >1 times will have a problem because there is a high chance to get draw result. It doesn't have any correlation with fairness though.

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3 years ago

What 3 digits are in the thousands period in the number 9,827,273

Arada [10]

The numbers in the thousands period are 827

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3 years ago

Read 2 more answers

A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

ddd [48]

Answer:

Mean = 15.15

Standard deviation = 0.6062

Step-by-step explanation:

We are given a uniform distribution of quantity to be put in each bag.

Low and high filling weights:

14.1 pounds and 16.2 pounds

a = 14.1

b = 16.2

a) Mean:

$\mu = \displaystyle\frac{a+b}{2}\\\\\mu = \frac{14.1+16.2}{2} = 15.15$

b) Standard Deviation:

$\sigma = \sqrt{\displaystyle\frac{(b-a)^2}{12}}\\\\= \sqrt{\dfrac{(16.2-14.1)^2}{12}} = \sqrt{0.3675} = 0.6062$

4 0

2 years ago

Solve system by subsubstitution?<br> 14x-2y=46<br> -7x+y=-23

e-lub [12.9K]

$14x-2y=46 \\
-7x+y=-23 \\ \\
\hbox{solve the 2nd equation for y:} \\
-7x+y=-23 \\
y=7x-23 \\ \\
\hbox{substitute 7x-23 for y in the 1st equation:} \\
14x-2(7x-23)=46 \\
14x-14x+46=46 \\
14x-14x=46-46 \\
0=0 \\ \\
\boxed{\hbox{infinitely many solutions}}$

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3 years ago

The diagonal length of a rectangle is 25 inches, and the length of the rectangle is 9 inches.

diamong [38]

Answer:

Option C is the right answer.

Step-by-step explanation:

Given that:

Length of diagonal = 25 inches

Length of rectangle = 9 inches

Width of rectangle will be one of the two legs of right angled triangle and the diagonal will be the hypotenuse.

Using Pythagorean theorem;

$a^2+b^2=c^2\\(9)^2+w^2=(25)^2\\81 + w^2 = 625 \\w^2 = 625-81\\w^2 = 544$

Taking square root;

$\sqrt{w^2}=\sqrt{544}\\w=23.3$

Therefore,

Option C is the right answer.

3 0

2 years ago