Number of stickers is less than 1145 but greater than 1100. How many stickers?

Can someone tell me step by step how to solve this?

sasho [114]

Answer:

Step-by-step explanation:

I take it that this is some sort of ratio. Start by solving the brackets on the left.

Brackets: 1/3 - 1/10

Brackets: 10/30 - 3/30

Brackets: 7/30

Brackets^2: 49/900

Brackets^2 - 1/5: 49/900 - 180/900

Brackets^2 - 1/5: -131/900

(2/5)^2 = 4/25

The way this read, it should be

$\frac{\frac{-131}{900} }{\frac{4}{25} }$

Which when you invert and multiply becomes

$\frac{-131}{900} * \frac{25}{4}$

which finally becomes

$\frac{-131}{144}$

7 0

2 years ago

The first three steps in determining the solution set of the system of equations algebraically are shown.

jolli1 [7]

Since both are equivalent to y, the equations must be equivalent.
x^2-x-3= -3x+5
x^2+2x-8=0

(x+4)(x-2)=0
x=-4, x=2

Plug the values of x in to either equation
y=-3(-4)+5
y= 12+5
y=17

y= -3(2)+5
y=-6+5
y=-1

Final answer: (-4,17) and (2,-1)

8 0

3 years ago

Read 2 more answers

Omg, I need help! A builder is buying property where she can build new houses. The line plot shows the sizes for each house. 1/6

klemol [59]

Answer:

Average size of the lots = ⅓ acre

Step-by-step explanation:

The question incomplete without specifying what we are to determine.

Question:A builder is buying property where she can build new houses. The line plot shows the sizes for each house. 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X's. Organize the information in a line plot. What is the average size of the lots? _________ acre

Help anyone?

Solution:

We are asked to organize the information in a line plot. See attachment for the line plot.

Given: 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X'sIn no particular order, the sizes of the lots are:1/6, 1/6, 1/6, 1/6, 1/6, 1/6, 1/3, 1/3, 1/3, 1/2, 1/2, 1/2, 1/2, 1/2 and 1/2 acre.

Let's count the number of lot for each size given.

For 1/6: there are 6 X's on the line plot of 1/6 number of lot for 1/6

= the lot × number of times it occurs

= (1/6) × 6 = 6/6 = 1 acre

For 1/3: there are 3 X's on the line plot of 1/3 number of lot for 1/3 = the lot × number of times it occurs

= (1/3) × 3 = 3/3 = 1 acre

For 1/2: there are 6 X's on the line plot of 1/2 number of lot for 1/2

= the lot × number of times it occurs

= (1/2) × 6 = 6/2= 3 acres

To find average size of the lots, we would sum all lot for each given size then divide by the total number of lots given.Sum of all lot for each given size = 1+1+3

Sum of all lot for each given size = 5

The total number of lots given = 15

Average size of the lots = 5/15 = 1/3

Average size of the lots = ⅓ acre