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mariarad [96]
3 years ago
5

At a flea market, used computer games are sold at the prices shown in the table below.

Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0
There’s no question....
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-8x + 7y=-16<br> 4x + y=-28
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Answer:

x=-5

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Step-by-step explanation:

let first equation be equation 1

let second equation be equation 2

so we gather the like terms

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3 years ago
The initial size of the population is 300. After 1 day the population has grown to 800. Estimate the population after 6 days. (R
Cloud [144]

Solution :

Given initial population = 300

Final population after 1 day = 800

Number of days = 6

∴ $\frac{dP}{dt} =kt^{1/2} $

P(0) = 300    P(1) = 300

We need to find P(8).

$dP = kt^{1/2} dt$

$ \int 1 dP = \int kt^{1/2} dt$

$P(t) = k \left(\frac{t^{3/2}}{3/2}\right)+c$

$P(t)= \frac{2k}{3}t^{3/2} + c$

When P(0) = 300

$300 = \frac{2k}{3} (0)^{3/2} + c$

∴ c = 300

∴ $P(t)= \frac{2k}{3}t^{3/2} + 300$

When P(1) = 800

$800 = \frac{2k}{3} (1)^{3/2} + 300$

$500 = \frac{2k}{3}$

∴ k = 750

$P(t)= 500t^{3/2} + 300$

So, P(8) is

$P(t)= 500(8)^{3/2} + 300$

        = 11,614

So the population becomes 11,614 after 8 days.

8 0
3 years ago
These circles are: <br> A. concentric<br> B. none of these<br> C. tangent<br> D. congruent
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They are tangent to eachother as they intersect at one place and one place only.
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