Question

PLZ help super fast thanks

Answer 1

Answer:

B. $\frac{1}{x^2y^7}$

Step-by-step explanation:

Given:

$(x^3y^{-2}z)(x^{-5}y^{-5}z^{-1})$

Hence Solving the given expression we get;

By Law of Indices which states;

$(a^xb^yc^z)(a^pb^qc^r) = a^{x+p}b^{y+q}c^{z+r}$

Hence we get;

$x^{3+(-5)}y^{(-2)+(-5)}z^{1+(-1)}\\\\x^{3-5}y^{-2-5}z^{1-1}\\\\x^{-2}y^{-7}$

Also We know that

$a^{-6} =\frac{1}{a^6}$

So,

$\frac{1}{x^2y^7}$