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lisov135 [29]
2 years ago
13

PLEASE HELP WILL MARK BRAINLYIST HELP

Mathematics
2 answers:
Sliva [168]2 years ago
4 0
Easy it 7/8. Hope this help. Don’t forget to mark me as BRAINLYIST THANKS
Gre4nikov [31]2 years ago
3 0
Your answer is A. 1/8 gallons/daily
Explanation
1/2 divided by 4 = 1/8

Just trust me, and mark me brainliest ty

Have a nice day!
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if Penelope's car has an average fuel consumption of 3 miles per gallon and she uses 9.5 gallons how far did she drive ​
KatRina [158]

Answer:

approximately 3.16 repeated

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Katya made another set of dolls. In the new set, the largest doll has a diameter of 8.75 cm and a height of 15.6 cm. Is this a d
Natali5045456 [20]

<em>Complete Question:</em>

<em>Katya creates handmade sets of dolls, which is sold to craft and souvenir stores. The first set of dolls has a middle diameter of 7cm and a height of 12cm.</em>

<em>Katya made another set of dolls. In the new set, the largest doll has a diameter of 8.75 cm and a height of 15.6 cm. Is this a dilation of the first set of dolls? </em>

<em></em>

Answer:

The new set is not a dilation of the first set

Step-by-step explanation:

Given

First Set:

Height = 12cm

Diameter = 7cm

New Set:

Height = 15.6cm

Diameter = 8.75cm

Required

Determine if the new set is a dilation of the second

To do this, we pass through the following steps:

1. Divide the height of the first set by the new set

2. Divide the diameter of the first set by the new set

3. Result in (1) and (2) must be equal if the new set is a dilation of the first set

Following the steps above:

(1)

Height\ Ratio = \frac{H_2}{H_1}

Height\ Ratio = \frac{15.6}{12}

Height\ Ratio = 1.3

(2)

Diameter\ Ratio = \frac{D_2}{D_1}

Diameter\ Ratio = \frac{8.75}{7}

Diameter\ Ratio = 1.25

(3) Make comparison

The ratio in (1) does not equal the ratio in (2)

i.e.

1.3 \neq 1.25

<em>Hence, the new set is not a dilation of the first set</em>

7 0
3 years ago
Solve the system of inequalities:<br> 6y≥42<br> 4y+12≤0
Hatshy [7]

Answer:

no solution

Step-by-step explanation:

6y≥42

Divide each side by 6

6y/6≥42/6

y≥7

Then solve the second one

4y+12≤0

Subtract 12 from each side

4y+12-12≤0-12

4y ≤-12

Divide each side by 4

4y/4 ≤-12/4

y ≤-3

There is no solution since there is no overlap

8 0
3 years ago
Consider a tree T storing 100,000 entries. What is the worst-case height of T in the following cases?
Darina [25.2K]

Answer:

Step-by-step explanation:

a.) The worst-case height of an AVL tree or red-black tree with 100,000 entries is 2 log 100, 000.

b.) A (2, 4) tree storing these same number of entries would have a worst-case height of log 100, 000.

c.) A red-black tree with 100,000 entries is 2 log 100, 000

d.) The worst-case height of T is 100,000.

e.)  A binary search tree storing such a set would have a worst-case height of 100,000.

6 0
3 years ago
Can someone help me please!!
hodyreva [135]

Answer:

  1. idk

Step-by-step explanation:

i just need points :/ v

8 0
3 years ago
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